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Use .as_ref() in lieu of &** (#5874)

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I find this less opaque (and often more succinct).
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Charlie Marsh 2023-07-18 20:49:13 -04:00 • committed by GitHub
parent 7ffcd93afd
commit 626d8dc2cc
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7 changed files with 17 additions and 21 deletions
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6
crates/ruff_python_ast/src/all.rs
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@ -65,7 +65,7 @@ where
}) => {
// Allow `tuple()` and `list()` calls.
if keywords.is_empty() && args.len() <= 1 {
if let Expr::Name(ast::ExprName { id, .. }) = &**func {
if let Expr::Name(ast::ExprName { id, .. }) = func.as_ref() {
let id = id.as_str();
if id == "tuple" || id == "list" {
if is_builtin(id) {
@ -106,7 +106,7 @@ where
Stmt::AugAssign(ast::StmtAugAssign { value, .. }) => Some(value),
_ => None,
} {
if let Expr::BinOp(ast::ExprBinOp { left, right, .. }) = &**value {
if let Expr::BinOp(ast::ExprBinOp { left, right, .. }) = value.as_ref() {
let mut current_left = left;
let mut current_right = right;
loop {
@ -119,7 +119,7 @@ where
// Process the left side, which can be a "real" value or the "rest" of the
// binary operation.
if let Expr::BinOp(ast::ExprBinOp { left, right, .. }) = &**current_left {
if let Expr::BinOp(ast::ExprBinOp { left, right, .. }) = current_left.as_ref() {
current_left = left;
current_right = right;
} else {