Rename Red Knot (#17820)

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# Callable
References:
- <https://typing.python.org/en/latest/spec/callables.html#callable>
Note that `typing.Callable` is deprecated at runtime, in favour of `collections.abc.Callable` (see:
<https://docs.python.org/3/library/typing.html#deprecated-aliases>). However, removal of
`typing.Callable` is not currently planned, and the canonical location of the stub for the symbol in
typeshed is still `typing.pyi`.
## Invalid forms
The `Callable` special form requires _exactly_ two arguments where the first argument is either a
parameter type list, parameter specification, `typing.Concatenate`, or `...` and the second argument
is the return type. Here, we explore various invalid forms.
### Empty
A bare `Callable` without any type arguments:
```py
from typing import Callable
def _(c: Callable):
reveal_type(c) # revealed: (...) -> Unknown
```
### Invalid parameter type argument
When it's not a list:
```py
from typing import Callable
# error: [invalid-type-form] "The first argument to `Callable` must be either a list of types, ParamSpec, Concatenate, or `...`"
def _(c: Callable[int, str]):
reveal_type(c) # revealed: (...) -> Unknown
```
Or, when it's a literal type:
```py
# error: [invalid-type-form] "The first argument to `Callable` must be either a list of types, ParamSpec, Concatenate, or `...`"
def _(c: Callable[42, str]):
reveal_type(c) # revealed: (...) -> Unknown
```
Or, when one of the parameter type is invalid in the list:
```py
# error: [invalid-type-form] "Int literals are not allowed in this context in a type expression"
# error: [invalid-type-form] "Boolean literals are not allowed in this context in a type expression"
def _(c: Callable[[int, 42, str, False], None]):
# revealed: (int, Unknown, str, Unknown, /) -> None
reveal_type(c)
```
### Missing return type
Using a parameter list:
```py
from typing import Callable
# error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
def _(c: Callable[[int, str]]):
reveal_type(c) # revealed: (...) -> Unknown
```
Or, an ellipsis:
```py
# error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
def _(c: Callable[...]):
reveal_type(c) # revealed: (...) -> Unknown
```
Or something else that's invalid in a type expression generally:
```py
# fmt: off
def _(c: Callable[ # error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
{1, 2} # error: [invalid-type-form] "The first argument to `Callable` must be either a list of types, ParamSpec, Concatenate, or `...`"
]
):
reveal_type(c) # revealed: (...) -> Unknown
```
### More than two arguments
We can't reliably infer the callable type if there are more then 2 arguments because we don't know
which argument corresponds to either the parameters or the return type.
```py
from typing import Callable
# error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
def _(c: Callable[[int], str, str]):
reveal_type(c) # revealed: (...) -> Unknown
```
### List as the second argument
```py
from typing import Callable
# fmt: off
def _(c: Callable[
int, # error: [invalid-type-form] "The first argument to `Callable` must be either a list of types, ParamSpec, Concatenate, or `...`"
[str] # error: [invalid-type-form] "List literals are not allowed in this context in a type expression"
]
):
reveal_type(c) # revealed: (...) -> Unknown
```
### List as both arguments
```py
from typing import Callable
# error: [invalid-type-form] "List literals are not allowed in this context in a type expression"
def _(c: Callable[[int], [str]]):
reveal_type(c) # revealed: (int, /) -> Unknown
```
### Three list arguments
```py
from typing import Callable
# fmt: off
def _(c: Callable[ # error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
[int],
[str], # error: [invalid-type-form] "List literals are not allowed in this context in a type expression"
[bytes] # error: [invalid-type-form] "List literals are not allowed in this context in a type expression"
]
):
reveal_type(c) # revealed: (...) -> Unknown
```
## Simple
A simple `Callable` with multiple parameters and a return type:
```py
from typing import Callable
def _(c: Callable[[int, str], int]):
reveal_type(c) # revealed: (int, str, /) -> int
```
## Union
```py
from typing import Callable, Union
def _(
c: Callable[[Union[int, str]], int] | None,
d: None | Callable[[Union[int, str]], int],
e: None | Callable[[Union[int, str]], int] | int,
):
reveal_type(c) # revealed: ((int | str, /) -> int) | None
reveal_type(d) # revealed: None | ((int | str, /) -> int)
reveal_type(e) # revealed: None | ((int | str, /) -> int) | int
```
## Intersection
```py
from typing import Callable, Union
from ty_extensions import Intersection, Not
def _(
c: Intersection[Callable[[Union[int, str]], int], int],
d: Intersection[int, Callable[[Union[int, str]], int]],
e: Intersection[int, Callable[[Union[int, str]], int], str],
f: Intersection[Not[Callable[[int, str], Intersection[int, str]]]],
):
reveal_type(c) # revealed: ((int | str, /) -> int) & int
reveal_type(d) # revealed: int & ((int | str, /) -> int)
reveal_type(e) # revealed: int & ((int | str, /) -> int) & str
reveal_type(f) # revealed: ~((int, str, /) -> int & str)
```
## Nested
A nested `Callable` as one of the parameter types:
```py
from typing import Callable
def _(c: Callable[[Callable[[int], str]], int]):
reveal_type(c) # revealed: ((int, /) -> str, /) -> int
```
And, as the return type:
```py
def _(c: Callable[[int, str], Callable[[int], int]]):
reveal_type(c) # revealed: (int, str, /) -> (int, /) -> int
```
## Gradual form
The `Callable` special form supports the use of `...` in place of the list of parameter types. This
is a [gradual form] indicating that the type is consistent with any input signature:
```py
from typing import Callable
def gradual_form(c: Callable[..., str]):
reveal_type(c) # revealed: (...) -> str
```
## Using `typing.Concatenate`
Using `Concatenate` as the first argument to `Callable`:
```py
from typing_extensions import Callable, Concatenate
def _(c: Callable[Concatenate[int, str, ...], int]):
# TODO: Should reveal the correct signature
reveal_type(c) # revealed: (...) -> int
```
And, as one of the parameter types:
```py
def _(c: Callable[[Concatenate[int, str, ...], int], int]):
# TODO: Should reveal the correct signature
reveal_type(c) # revealed: (...) -> int
```
## Using `typing.ParamSpec`
```toml
[environment]
python-version = "3.12"
```
Using a `ParamSpec` in a `Callable` annotation:
```py
from typing_extensions import Callable
# TODO: Not an error; remove once `ParamSpec` is supported
# error: [invalid-type-form]
def _[**P1](c: Callable[P1, int]):
reveal_type(c) # revealed: (...) -> Unknown
```
And, using the legacy syntax:
```py
from typing_extensions import ParamSpec
P2 = ParamSpec("P2")
# TODO: Not an error; remove once `ParamSpec` is supported
# error: [invalid-type-form]
def _(c: Callable[P2, int]):
reveal_type(c) # revealed: (...) -> Unknown
```
## Using `typing.Unpack`
Using the unpack operator (`*`):
```py
from typing_extensions import Callable, TypeVarTuple
Ts = TypeVarTuple("Ts")
def _(c: Callable[[int, *Ts], int]):
# TODO: Should reveal the correct signature
reveal_type(c) # revealed: (...) -> int
```
And, using the legacy syntax using `Unpack`:
```py
from typing_extensions import Unpack
def _(c: Callable[[int, Unpack[Ts]], int]):
# TODO: Should reveal the correct signature
reveal_type(c) # revealed: (...) -> int
```
## Member lookup
```py
from typing import Callable
def _(c: Callable[[int], int]):
reveal_type(c.__init__) # revealed: def __init__(self) -> None
reveal_type(c.__class__) # revealed: type
reveal_type(c.__call__) # revealed: (int, /) -> int
```
[gradual form]: https://typing.python.org/en/latest/spec/glossary.html#term-gradual-form