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Rename Red Knot (#17820)
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# Callable
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References:
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- <https://typing.python.org/en/latest/spec/callables.html#callable>
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Note that `typing.Callable` is deprecated at runtime, in favour of `collections.abc.Callable` (see:
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<https://docs.python.org/3/library/typing.html#deprecated-aliases>). However, removal of
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`typing.Callable` is not currently planned, and the canonical location of the stub for the symbol in
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typeshed is still `typing.pyi`.
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## Invalid forms
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The `Callable` special form requires _exactly_ two arguments where the first argument is either a
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parameter type list, parameter specification, `typing.Concatenate`, or `...` and the second argument
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is the return type. Here, we explore various invalid forms.
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### Empty
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A bare `Callable` without any type arguments:
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```py
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from typing import Callable
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def _(c: Callable):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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### Invalid parameter type argument
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When it's not a list:
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```py
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from typing import Callable
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# error: [invalid-type-form] "The first argument to `Callable` must be either a list of types, ParamSpec, Concatenate, or `...`"
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def _(c: Callable[int, str]):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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Or, when it's a literal type:
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```py
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# error: [invalid-type-form] "The first argument to `Callable` must be either a list of types, ParamSpec, Concatenate, or `...`"
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def _(c: Callable[42, str]):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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Or, when one of the parameter type is invalid in the list:
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```py
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# error: [invalid-type-form] "Int literals are not allowed in this context in a type expression"
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# error: [invalid-type-form] "Boolean literals are not allowed in this context in a type expression"
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def _(c: Callable[[int, 42, str, False], None]):
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# revealed: (int, Unknown, str, Unknown, /) -> None
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reveal_type(c)
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```
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### Missing return type
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Using a parameter list:
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```py
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from typing import Callable
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# error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
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def _(c: Callable[[int, str]]):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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Or, an ellipsis:
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```py
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# error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
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def _(c: Callable[...]):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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Or something else that's invalid in a type expression generally:
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```py
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# fmt: off
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def _(c: Callable[ # error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
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{1, 2} # error: [invalid-type-form] "The first argument to `Callable` must be either a list of types, ParamSpec, Concatenate, or `...`"
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]
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):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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### More than two arguments
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We can't reliably infer the callable type if there are more then 2 arguments because we don't know
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which argument corresponds to either the parameters or the return type.
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```py
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from typing import Callable
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# error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
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def _(c: Callable[[int], str, str]):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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### List as the second argument
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```py
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from typing import Callable
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# fmt: off
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def _(c: Callable[
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int, # error: [invalid-type-form] "The first argument to `Callable` must be either a list of types, ParamSpec, Concatenate, or `...`"
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[str] # error: [invalid-type-form] "List literals are not allowed in this context in a type expression"
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]
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):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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### List as both arguments
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```py
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from typing import Callable
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# error: [invalid-type-form] "List literals are not allowed in this context in a type expression"
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def _(c: Callable[[int], [str]]):
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reveal_type(c) # revealed: (int, /) -> Unknown
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```
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### Three list arguments
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```py
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from typing import Callable
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# fmt: off
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def _(c: Callable[ # error: [invalid-type-form] "Special form `typing.Callable` expected exactly two arguments (parameter types and return type)"
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[int],
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[str], # error: [invalid-type-form] "List literals are not allowed in this context in a type expression"
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[bytes] # error: [invalid-type-form] "List literals are not allowed in this context in a type expression"
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]
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):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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## Simple
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A simple `Callable` with multiple parameters and a return type:
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```py
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from typing import Callable
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def _(c: Callable[[int, str], int]):
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reveal_type(c) # revealed: (int, str, /) -> int
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```
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## Union
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```py
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from typing import Callable, Union
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def _(
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c: Callable[[Union[int, str]], int] | None,
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d: None | Callable[[Union[int, str]], int],
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e: None | Callable[[Union[int, str]], int] | int,
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):
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reveal_type(c) # revealed: ((int | str, /) -> int) | None
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reveal_type(d) # revealed: None | ((int | str, /) -> int)
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reveal_type(e) # revealed: None | ((int | str, /) -> int) | int
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```
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## Intersection
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```py
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from typing import Callable, Union
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from ty_extensions import Intersection, Not
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def _(
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c: Intersection[Callable[[Union[int, str]], int], int],
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d: Intersection[int, Callable[[Union[int, str]], int]],
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e: Intersection[int, Callable[[Union[int, str]], int], str],
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f: Intersection[Not[Callable[[int, str], Intersection[int, str]]]],
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):
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reveal_type(c) # revealed: ((int | str, /) -> int) & int
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reveal_type(d) # revealed: int & ((int | str, /) -> int)
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reveal_type(e) # revealed: int & ((int | str, /) -> int) & str
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reveal_type(f) # revealed: ~((int, str, /) -> int & str)
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```
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## Nested
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A nested `Callable` as one of the parameter types:
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```py
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from typing import Callable
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def _(c: Callable[[Callable[[int], str]], int]):
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reveal_type(c) # revealed: ((int, /) -> str, /) -> int
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```
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And, as the return type:
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```py
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def _(c: Callable[[int, str], Callable[[int], int]]):
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reveal_type(c) # revealed: (int, str, /) -> (int, /) -> int
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```
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## Gradual form
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The `Callable` special form supports the use of `...` in place of the list of parameter types. This
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is a [gradual form] indicating that the type is consistent with any input signature:
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```py
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from typing import Callable
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def gradual_form(c: Callable[..., str]):
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reveal_type(c) # revealed: (...) -> str
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```
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## Using `typing.Concatenate`
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Using `Concatenate` as the first argument to `Callable`:
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```py
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from typing_extensions import Callable, Concatenate
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def _(c: Callable[Concatenate[int, str, ...], int]):
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# TODO: Should reveal the correct signature
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reveal_type(c) # revealed: (...) -> int
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```
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And, as one of the parameter types:
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```py
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def _(c: Callable[[Concatenate[int, str, ...], int], int]):
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# TODO: Should reveal the correct signature
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reveal_type(c) # revealed: (...) -> int
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```
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## Using `typing.ParamSpec`
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```toml
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[environment]
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python-version = "3.12"
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```
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Using a `ParamSpec` in a `Callable` annotation:
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```py
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from typing_extensions import Callable
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# TODO: Not an error; remove once `ParamSpec` is supported
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# error: [invalid-type-form]
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def _[**P1](c: Callable[P1, int]):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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And, using the legacy syntax:
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```py
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from typing_extensions import ParamSpec
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P2 = ParamSpec("P2")
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# TODO: Not an error; remove once `ParamSpec` is supported
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# error: [invalid-type-form]
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def _(c: Callable[P2, int]):
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reveal_type(c) # revealed: (...) -> Unknown
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```
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## Using `typing.Unpack`
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Using the unpack operator (`*`):
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```py
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from typing_extensions import Callable, TypeVarTuple
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Ts = TypeVarTuple("Ts")
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def _(c: Callable[[int, *Ts], int]):
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# TODO: Should reveal the correct signature
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reveal_type(c) # revealed: (...) -> int
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```
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And, using the legacy syntax using `Unpack`:
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```py
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from typing_extensions import Unpack
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def _(c: Callable[[int, Unpack[Ts]], int]):
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# TODO: Should reveal the correct signature
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reveal_type(c) # revealed: (...) -> int
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```
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## Member lookup
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```py
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from typing import Callable
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def _(c: Callable[[int], int]):
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reveal_type(c.__init__) # revealed: def __init__(self) -> None
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reveal_type(c.__class__) # revealed: type
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reveal_type(c.__call__) # revealed: (int, /) -> int
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```
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[gradual form]: https://typing.python.org/en/latest/spec/glossary.html#term-gradual-form
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