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Rename Red Knot (#17820)
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crates/ty_python_semantic/resources/mdtest/binary/instances.md
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crates/ty_python_semantic/resources/mdtest/binary/instances.md
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# Binary operations on instances
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Binary operations in Python are implemented by means of magic double-underscore methods.
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For references, see:
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- <https://snarky.ca/unravelling-binary-arithmetic-operations-in-python/>
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- <https://docs.python.org/3/reference/datamodel.html#emulating-numeric-types>
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## Operations
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We support inference for all Python's binary operators: `+`, `-`, `*`, `@`, `/`, `//`, `%`, `**`,
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`<<`, `>>`, `&`, `^`, and `|`.
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```py
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class A:
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def __add__(self, other) -> "A":
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return self
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def __sub__(self, other) -> "A":
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return self
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def __mul__(self, other) -> "A":
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return self
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def __matmul__(self, other) -> "A":
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return self
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def __truediv__(self, other) -> "A":
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return self
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def __floordiv__(self, other) -> "A":
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return self
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def __mod__(self, other) -> "A":
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return self
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def __pow__(self, other) -> "A":
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return self
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def __lshift__(self, other) -> "A":
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return self
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def __rshift__(self, other) -> "A":
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return self
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def __and__(self, other) -> "A":
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return self
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def __xor__(self, other) -> "A":
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return self
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def __or__(self, other) -> "A":
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return self
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class B: ...
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reveal_type(A() + B()) # revealed: A
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reveal_type(A() - B()) # revealed: A
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reveal_type(A() * B()) # revealed: A
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reveal_type(A() @ B()) # revealed: A
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reveal_type(A() / B()) # revealed: A
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reveal_type(A() // B()) # revealed: A
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reveal_type(A() % B()) # revealed: A
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reveal_type(A() ** B()) # revealed: A
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reveal_type(A() << B()) # revealed: A
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reveal_type(A() >> B()) # revealed: A
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reveal_type(A() & B()) # revealed: A
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reveal_type(A() ^ B()) # revealed: A
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reveal_type(A() | B()) # revealed: A
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```
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## Reflected
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We also support inference for reflected operations:
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```py
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class A:
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def __radd__(self, other) -> "A":
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return self
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def __rsub__(self, other) -> "A":
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return self
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def __rmul__(self, other) -> "A":
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return self
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def __rmatmul__(self, other) -> "A":
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return self
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def __rtruediv__(self, other) -> "A":
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return self
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def __rfloordiv__(self, other) -> "A":
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return self
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def __rmod__(self, other) -> "A":
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return self
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def __rpow__(self, other) -> "A":
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return self
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def __rlshift__(self, other) -> "A":
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return self
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def __rrshift__(self, other) -> "A":
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return self
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def __rand__(self, other) -> "A":
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return self
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def __rxor__(self, other) -> "A":
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return self
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def __ror__(self, other) -> "A":
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return self
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class B: ...
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reveal_type(B() + A()) # revealed: A
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reveal_type(B() - A()) # revealed: A
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reveal_type(B() * A()) # revealed: A
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reveal_type(B() @ A()) # revealed: A
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reveal_type(B() / A()) # revealed: A
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reveal_type(B() // A()) # revealed: A
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reveal_type(B() % A()) # revealed: A
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reveal_type(B() ** A()) # revealed: A
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reveal_type(B() << A()) # revealed: A
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reveal_type(B() >> A()) # revealed: A
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reveal_type(B() & A()) # revealed: A
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reveal_type(B() ^ A()) # revealed: A
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reveal_type(B() | A()) # revealed: A
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```
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## Returning a different type
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The magic methods aren't required to return the type of `self`:
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```py
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class A:
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def __add__(self, other) -> int:
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return 1
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def __rsub__(self, other) -> int:
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return 1
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class B: ...
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reveal_type(A() + B()) # revealed: int
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reveal_type(B() - A()) # revealed: int
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```
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## Non-reflected precedence in general
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In general, if the left-hand side defines `__add__` and the right-hand side defines `__radd__` and
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the right-hand side is not a subtype of the left-hand side, `lhs.__add__` will take precedence:
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```py
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class A:
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def __add__(self, other: "B") -> int:
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return 42
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class B:
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def __radd__(self, other: "A") -> str:
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return "foo"
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reveal_type(A() + B()) # revealed: int
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# Edge case: C is a subtype of C, *but* if the two sides are of *equal* types,
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# the lhs *still* takes precedence
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class C:
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def __add__(self, other: "C") -> int:
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return 42
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def __radd__(self, other: "C") -> str:
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return "foo"
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reveal_type(C() + C()) # revealed: int
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```
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## Reflected precedence for subtypes (in some cases)
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If the right-hand operand is a subtype of the left-hand operand and has a different implementation
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of the reflected method, the reflected method on the right-hand operand takes precedence.
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```py
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class A:
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def __add__(self, other) -> str:
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return "foo"
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def __radd__(self, other) -> str:
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return "foo"
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class MyString(str): ...
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class B(A):
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def __radd__(self, other) -> MyString:
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return MyString()
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reveal_type(A() + B()) # revealed: MyString
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# N.B. Still a subtype of `A`, even though `A` does not appear directly in the class's `__bases__`
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class C(B): ...
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reveal_type(A() + C()) # revealed: MyString
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```
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## Reflected precedence 2
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If the right-hand operand is a subtype of the left-hand operand, but does not override the reflected
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method, the left-hand operand's non-reflected method still takes precedence:
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```py
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class A:
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def __add__(self, other) -> str:
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return "foo"
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def __radd__(self, other) -> int:
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return 42
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class B(A): ...
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reveal_type(A() + B()) # revealed: str
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```
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## Only reflected supported
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For example, at runtime, `(1).__add__(1.2)` is `NotImplemented`, but `(1.2).__radd__(1) == 2.2`,
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meaning that `1 + 1.2` succeeds at runtime (producing `2.2`). The runtime tries the second one only
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if the first one returns `NotImplemented` to signal failure.
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Typeshed and other stubs annotate dunder-method calls that would return `NotImplemented` as being
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"illegal" calls. `int.__add__` is annotated as only "accepting" `int`s, even though it
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strictly-speaking "accepts" any other object without raising an exception -- it will simply return
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`NotImplemented`, allowing the runtime to try the `__radd__` method of the right-hand operand as
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well.
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```py
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class A:
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def __sub__(self, other: "A") -> "A":
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return A()
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class B:
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def __rsub__(self, other: A) -> "B":
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return B()
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reveal_type(A() - B()) # revealed: B
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```
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## Callable instances as dunders
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Believe it or not, this is supported at runtime:
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```py
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class A:
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def __call__(self, other) -> int:
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return 42
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class B:
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__add__ = A()
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reveal_type(B() + B()) # revealed: Unknown | int
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```
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Note that we union with `Unknown` here because `__add__` is not declared. We do infer just `int` if
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the callable is declared:
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```py
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class B2:
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__add__: A = A()
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reveal_type(B2() + B2()) # revealed: int
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```
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## Integration test: numbers from typeshed
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We get less precise results from binary operations on float/complex literals due to the special case
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for annotations of `float` or `complex`, which applies also to return annotations for typeshed
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dunder methods. Perhaps we could have a special-case on the special-case, to exclude these typeshed
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return annotations from the widening, and preserve a bit more precision here?
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```py
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reveal_type(3j + 3.14) # revealed: int | float | complex
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reveal_type(4.2 + 42) # revealed: int | float
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reveal_type(3j + 3) # revealed: int | float | complex
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reveal_type(3.14 + 3j) # revealed: int | float | complex
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reveal_type(42 + 4.2) # revealed: int | float
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reveal_type(3 + 3j) # revealed: int | float | complex
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def _(x: bool, y: int):
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reveal_type(x + y) # revealed: int
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reveal_type(4.2 + x) # revealed: int | float
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reveal_type(y + 4.12) # revealed: int | float
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```
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## With literal types
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When we have a literal type for one operand, we're able to fall back to the instance handling for
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its instance super-type.
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```py
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class A:
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def __add__(self, other) -> "A":
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return self
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def __radd__(self, other) -> "A":
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return self
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reveal_type(A() + 1) # revealed: A
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reveal_type(1 + A()) # revealed: A
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reveal_type(A() + "foo") # revealed: A
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reveal_type("foo" + A()) # revealed: A
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reveal_type(A() + b"foo") # revealed: A
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# TODO should be `A` since `bytes.__add__` doesn't support `A` instances
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reveal_type(b"foo" + A()) # revealed: bytes
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reveal_type(A() + ()) # revealed: A
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# TODO this should be `A`, since `tuple.__add__` doesn't support `A` instances
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reveal_type(() + A()) # revealed: @Todo(full tuple[...] support)
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literal_string_instance = "foo" * 1_000_000_000
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# the test is not testing what it's meant to be testing if this isn't a `LiteralString`:
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reveal_type(literal_string_instance) # revealed: LiteralString
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reveal_type(A() + literal_string_instance) # revealed: A
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reveal_type(literal_string_instance + A()) # revealed: A
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```
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## Operations involving instances of classes inheriting from `Any`
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`Any` and `Unknown` represent a set of possible runtime objects, wherein the bounds of the set are
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unknown. Whether the left-hand operand's dunder or the right-hand operand's reflected dunder depends
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on whether the right-hand operand is an instance of a class that is a subclass of the left-hand
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operand's class and overrides the reflected dunder. In the following example, because of the
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unknowable nature of `Any`/`Unknown`, we must consider both possibilities: `Any`/`Unknown` might
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resolve to an unknown third class that inherits from `X` and overrides `__radd__`; but it also might
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not. Thus, the correct answer here for the `reveal_type` is `int | Unknown`.
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```py
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from does_not_exist import Foo # error: [unresolved-import]
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reveal_type(Foo) # revealed: Unknown
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class X:
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def __add__(self, other: object) -> int:
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return 42
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class Y(Foo): ...
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# TODO: Should be `int | Unknown`; see above discussion.
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reveal_type(X() + Y()) # revealed: int
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```
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## Operations involving types with invalid `__bool__` methods
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<!-- snapshot-diagnostics -->
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```py
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class NotBoolable:
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__bool__: int = 3
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a = NotBoolable()
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# error: [unsupported-bool-conversion]
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10 and a and True
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```
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## Operations on class objects
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When operating on class objects, the corresponding dunder methods are looked up on the metaclass.
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```py
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from __future__ import annotations
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class Meta(type):
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def __add__(self, other: Meta) -> int:
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return 1
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def __lt__(self, other: Meta) -> bool:
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return True
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def __getitem__(self, key: int) -> str:
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return "a"
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class A(metaclass=Meta): ...
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class B(metaclass=Meta): ...
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reveal_type(A + B) # revealed: int
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# error: [unsupported-operator] "Operator `-` is unsupported between objects of type `Literal[A]` and `Literal[B]`"
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reveal_type(A - B) # revealed: Unknown
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reveal_type(A < B) # revealed: bool
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reveal_type(A > B) # revealed: bool
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# error: [unsupported-operator] "Operator `<=` is not supported for types `Literal[A]` and `Literal[B]`"
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reveal_type(A <= B) # revealed: Unknown
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reveal_type(A[0]) # revealed: str
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```
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## Unsupported
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### Dunder as instance attribute
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The magic method must exist on the class, not just on the instance:
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```py
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def add_impl(self, other) -> int:
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return 1
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class A:
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def __init__(self):
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self.__add__ = add_impl
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# error: [unsupported-operator] "Operator `+` is unsupported between objects of type `A` and `A`"
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# revealed: Unknown
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reveal_type(A() + A())
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```
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### Missing dunder
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```py
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class A: ...
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# error: [unsupported-operator]
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# revealed: Unknown
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reveal_type(A() + A())
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```
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### Wrong position
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A left-hand dunder method doesn't apply for the right-hand operand, or vice versa:
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```py
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class A:
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def __add__(self, other) -> int:
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return 1
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class B:
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def __radd__(self, other) -> int:
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return 1
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class C: ...
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# error: [unsupported-operator]
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# revealed: Unknown
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reveal_type(C() + A())
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# error: [unsupported-operator]
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# revealed: Unknown
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reveal_type(B() + C())
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```
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### Reflected dunder is not tried between two objects of the same type
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For the specific case where the left-hand operand is the exact same type as the right-hand operand,
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the reflected dunder of the right-hand operand is not tried; the runtime short-circuits after trying
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the unreflected dunder of the left-hand operand. For context, see
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[this mailing list discussion](https://mail.python.org/archives/list/python-dev@python.org/thread/7NZUCODEAPQFMRFXYRMGJXDSIS3WJYIV/).
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```py
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class Foo:
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def __radd__(self, other: "Foo") -> "Foo":
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return self
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# error: [unsupported-operator]
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# revealed: Unknown
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reveal_type(Foo() + Foo())
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```
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### Wrong type
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TODO: check signature and error if `other` is the wrong type
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