Handling `Literal` type in annotations.
Resolves: #13672
## Implementation
Since Literals are not a fully defined type in typeshed. I used a trick
to figure out when a special form is a literal.
When we are inferring assignment types I am checking if the type of that
assignment was resolved to typing.SpecialForm and the name of the target
is `Literal` if that is the case then I am re creating a new instance
type and set the known instance field to `KnownInstance:Literal`.
**Why not defining a new type?**
From this [issue](https://github.com/python/typeshed/issues/6219) I
learned that we want to resolve members to SpecialMethod class. So if we
create a new instance here we can rely on the member resolving in that
already exists.
## Tests
https://typing.readthedocs.io/en/latest/spec/literal.html#equivalence-of-two-literals
Since the type of the value inside Literal is evaluated as a
Literal(LiteralString, LiteralInt, ...) then the equality is only true
when types and value are equal.
https://typing.readthedocs.io/en/latest/spec/literal.html#legal-and-illegal-parameterizations
The illegal parameterizations are mostly implemented I'm currently
checking the slice expression and the slice type to make sure it's
valid.
https://typing.readthedocs.io/en/latest/spec/literal.html#shortening-unions-of-literals
---------
Co-authored-by: Carl Meyer <carl@astral.sh>
Co-authored-by: Alex Waygood <Alex.Waygood@Gmail.com>
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## Summary
- Remove `Type::Unbound`
- Handle (potential) unboundness as a concept orthogonal to the type
system (see new `Symbol` type)
- Improve existing and add new diagnostics related to (potential)
unboundness
closes#13671
## Test Plan
- Update existing markdown-based tests
- Add new tests for added/modified functionality
## Summary
This does two things:
- distribute negated intersections when building up intersections (i.e.
going from `A & ~(B & C)` to `(A & ~B) | (A & ~C)`) (fixing #13931)
## Test Plan
`cargo test`
## Summary
Fixes the bug described in #13514 where an unbound public type defaulted
to the type or `Unknown`, whereas it should only be the type if unbound.
## Test Plan
Added a new test case
---------
Co-authored-by: Carl Meyer <carl@astral.sh>
Support using `reveal_type` without importing it, as implied by the type
spec and supported by existing type checkers.
We use `typing_extensions.reveal_type` for the implicit built-in; this
way it exists on all Python versions. (It imports from `typing` on newer
Python versions.)
Emits an "undefined name" diagnostic whenever `reveal_type` is
referenced in this way (in addition to the revealed-type diagnostic when
it is called). This follows the mypy example (with `--enable-error-code
unimported-reveal`) and I think provides a good (and easily
understandable) balance for user experience. If you are using
`reveal_type` for quick temporary debugging, the additional
undefined-name diagnostic doesn't hinder that use case. If we make the
revealed-type diagnostic a non-failing one, the undefined-name
diagnostic can still be a failing diagnostic, helping prevent
accidentally leaving it in place. For any use cases where you want to
leave it in place, you can always import it to avoid the undefined-name
diagnostic.
In the future, we can easily provide configuration options to a) turn
off builtin-reveal_type altogether, and/or b) silence the undefined-name
diagnostic when using it, if we have users on either side (loving or
hating pseudo-builtin `reveal_type`) who are dissatisfied with this
compromise.
