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a1579d82d0
<!-- Thank you for contributing to Ruff/ty! To help us out with reviewing, please consider the following: - Does this pull request include a summary of the change? (See below.) - Does this pull request include a descriptive title? (Please prefix with `[ty]` for ty pull requests.) - Does this pull request include references to any relevant issues? --> ## Summary This PR also supresses the fix if the assignment expression target shadows one of the lambda's parameters. Fixes #18675 <!-- What's the purpose of the change? What does it do, and why? --> ## Test Plan Add regression tests. <!-- How was it tested? -->
63 lines
1.8 KiB
Python
63 lines
1.8 KiB
Python
_ = lambda: print() # [unnecessary-lambda]
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_ = lambda x, y: min(x, y) # [unnecessary-lambda]
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_ = lambda *args: f(*args) # [unnecessary-lambda]
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_ = lambda **kwargs: f(**kwargs) # [unnecessary-lambda]
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_ = lambda *args, **kwargs: f(*args, **kwargs) # [unnecessary-lambda]
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_ = lambda x, y, z, *args, **kwargs: f(x, y, z, *args, **kwargs) # [unnecessary-lambda]
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_ = lambda x: f(lambda x: x)(x) # [unnecessary-lambda]
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_ = lambda x, y: f(lambda x, y: x + y)(x, y) # [unnecessary-lambda]
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# default value in lambda parameters
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_ = lambda x=42: print(x)
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# lambda body is not a call
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_ = lambda x: x
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# ignore chained calls
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_ = lambda: chained().call()
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# lambda has kwargs but not the call
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_ = lambda **kwargs: f()
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# lambda has kwargs and the call has kwargs named differently
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_ = lambda **kwargs: f(**dict([('forty-two', 42)]))
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# lambda has kwargs and the call has unnamed kwargs
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_ = lambda **kwargs: f(**{1: 2})
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# lambda has starred parameters but not the call
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_ = lambda *args: f()
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# lambda has starred parameters and the call has starargs named differently
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_ = lambda *args: f(*list([3, 4]))
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# lambda has starred parameters and the call has unnamed starargs
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_ = lambda *args: f(*[3, 4])
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# lambda has parameters but not the call
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_ = lambda x: f()
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_ = lambda *x: f()
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_ = lambda **x: f()
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# lambda parameters and call args are not the same length
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_ = lambda x, y: f(x)
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# lambda parameters and call args are not in the same order
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_ = lambda x, y: f(y, x)
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# lambda parameters and call args are not the same
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_ = lambda x: f(y)
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# the call uses the lambda parameters
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_ = lambda x: x(x)
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_ = lambda x, y: x(x, y)
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_ = lambda x: z(lambda y: x + y)(x)
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# lambda uses an additional keyword
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_ = lambda *args: f(*args, y=1)
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_ = lambda *args: f(*args, y=x)
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# https://github.com/astral-sh/ruff/issues/18675
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_ = lambda x: (string := str)(x)
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_ = lambda x: ((x := 1) and str)(x)
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