Make tt generic over the span data

This commit is contained in:
Lukas Wirth 2023-01-31 11:49:49 +01:00
parent d805c74c51
commit 41a46a78f2
48 changed files with 806 additions and 569 deletions

View file

@ -2,7 +2,8 @@
//! format that works for our parser.
use syntax::{SyntaxKind, SyntaxKind::*, T};
use tt::buffer::TokenBuffer;
use crate::tt::buffer::TokenBuffer;
pub(crate) fn to_parser_input(buffer: &TokenBuffer<'_>) -> parser::Input {
let mut res = parser::Input::default();
@ -70,23 +71,25 @@ pub(crate) fn to_parser_input(buffer: &TokenBuffer<'_>) -> parser::Input {
cursor.bump()
}
Some(tt::buffer::TokenTreeRef::Subtree(subtree, _)) => {
if let Some(d) = subtree.delimiter_kind() {
res.push(match d {
tt::DelimiterKind::Parenthesis => T!['('],
tt::DelimiterKind::Brace => T!['{'],
tt::DelimiterKind::Bracket => T!['['],
});
if let Some(kind) = match subtree.delimiter.kind {
tt::DelimiterKind::Parenthesis => Some(T!['(']),
tt::DelimiterKind::Brace => Some(T!['{']),
tt::DelimiterKind::Bracket => Some(T!['[']),
tt::DelimiterKind::Invisible => None,
} {
res.push(kind);
}
cursor.subtree().unwrap()
}
None => match cursor.end() {
Some(subtree) => {
if let Some(d) = subtree.delimiter_kind() {
res.push(match d {
tt::DelimiterKind::Parenthesis => T![')'],
tt::DelimiterKind::Brace => T!['}'],
tt::DelimiterKind::Bracket => T![']'],
})
if let Some(kind) = match subtree.delimiter.kind {
tt::DelimiterKind::Parenthesis => Some(T![')']),
tt::DelimiterKind::Brace => Some(T!['}']),
tt::DelimiterKind::Bracket => Some(T![']']),
tt::DelimiterKind::Invisible => None,
} {
res.push(kind);
}
cursor.bump()
}