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Parse let expressions in order to support let chains

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We still need to reject freestanding `let` expressions: see https://github.com/rust-analyzer/rust-analyzer/issues/11320#issuecomment-1018212465.
This commit is contained in:
Chayim Refael Friedman 2022-01-23 04:21:09 +02:00
parent d6ed146a1c
commit de8633f15f
7 changed files with 99 additions and 67 deletions
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10
crates/parser/src/grammar/expressions.rs
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@ -29,6 +29,15 @@ fn expr_no_struct(p: &mut Parser) {
expr_bp(p, None, r, 1);
}
/// Parses the expression in `let pattern = expression`.
/// It needs to be parsed with lower precedence than `&&`, so that
/// `if let true = true && false` is parsed as `if (let true = true) && (true)`
/// and not `if let true = (true && true)`.
fn expr_let(p: &mut Parser) {
let r = Restrictions { forbid_structs: true, prefer_stmt: false };
expr_bp(p, None, r, 5);
}
pub(super) fn stmt(p: &mut Parser, semicolon: Semicolon) {
if p.eat(T![;]) {
return;
@ -185,6 +194,7 @@ fn current_op(p: &Parser) -> (u8, SyntaxKind) {
T![%] if p.at(T![%=]) => (1, T![%=]),
T![%] => (11, T![%]),
T![&] if p.at(T![&=]) => (1, T![&=]),
// If you update this, remember to update `expr_let()` too.
T![&] if p.at(T![&&]) => (4, T![&&]),
T![&] => (8, T![&]),
T![/] if p.at(T![/=]) => (1, T![/=]),