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bpo-37540: vectorcall: keyword names must be strings (GH-14682)

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The fact that keyword names are strings is now part of the vectorcall and `METH_FASTCALL` protocols. The biggest concrete change is that `_PyStack_UnpackDict` now checks that and raises `TypeError` if not.

CC @markshannon @vstinner 


https://bugs.python.org/issue37540
This commit is contained in:
Jeroen Demeyer 2019-08-16 12:41:27 +02:00 • committed by Miss Islington (bot)
parent f3cb68f2e4
commit 0567786d26
10 changed files with 43 additions and 46 deletions
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20
Python/getargs.c
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@ -2043,11 +2043,7 @@ find_keyword(PyObject *kwnames, PyObject *const *kwstack, PyObject *key)
if (kwname == key) {
return kwstack[i];
}
if (!PyUnicode_Check(kwname)) {
/* ignore non-string keyword keys:
an error will be raised below */
continue;
}
assert(PyUnicode_Check(kwname));
if (_PyUnicode_EQ(kwname, key)) {
return kwstack[i];
}
@ -2275,16 +2271,11 @@ vgetargskeywordsfast_impl(PyObject *const *args, Py_ssize_t nargs,
j++;
}
if (!PyUnicode_Check(keyword)) {
PyErr_SetString(PyExc_TypeError,
"keywords must be strings");
return cleanreturn(0, &freelist);
}
match = PySequence_Contains(kwtuple, keyword);
if (match <= 0) {
if (!match) {
PyErr_Format(PyExc_TypeError,
"'%U' is an invalid keyword "
"'%S' is an invalid keyword "
"argument for %.200s%s",
keyword,
(parser->fname == NULL) ? "this function" : parser->fname,
@ -2505,16 +2496,11 @@ _PyArg_UnpackKeywords(PyObject *const *args, Py_ssize_t nargs,
j++;
}
if (!PyUnicode_Check(keyword)) {
PyErr_SetString(PyExc_TypeError,
"keywords must be strings");
return NULL;
}
match = PySequence_Contains(kwtuple, keyword);
if (match <= 0) {
if (!match) {
PyErr_Format(PyExc_TypeError,
"'%U' is an invalid keyword "
"'%S' is an invalid keyword "
"argument for %.200s%s",
keyword,
(parser->fname == NULL) ? "this function" : parser->fname,