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Minor doc fixes.

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This commit is contained in:
Raymond Hettinger 2009-02-04 19:34:31 +00:00
parent 1e884d9f67
commit 11485b4869
3 changed files with 10 additions and 7 deletions
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2
Doc/glossary.rst
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@ -396,7 +396,7 @@ Glossary
also :term:`immutable`. also :term:`immutable`.
named tuple named tuple
Any tuple subclass whose indexable elements are also accessible using Any tuple-like class whose indexable elements are also accessible using
named attributes (for example, :func:`time.localtime` returns a named attributes (for example, :func:`time.localtime` returns a
tuple-like object where the *year* is accessible either with an tuple-like object where the *year* is accessible either with an
index such as ``t[0]`` or with a named attribute like ``t.tm_year``). index such as ``t[0]`` or with a named attribute like ``t.tm_year``).

6
Doc/library/itertools.rst
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@ -221,7 +221,7 @@ loops that truncate the stream.
class groupby(object): class groupby(object):
# [k for k, g in groupby('AAAABBBCCDAABBB')] --> A B C D A B # [k for k, g in groupby('AAAABBBCCDAABBB')] --> A B C D A B
# [(list(g)) for k, g in groupby('AAAABBBCCD')] --> AAAA BBB CC D # [list(g) for k, g in groupby('AAAABBBCCD')] --> AAAA BBB CC D
def __init__(self, iterable, key=None): def __init__(self, iterable, key=None):
if key is None: if key is None:
key = lambda x: x key = lambda x: x
@ -614,8 +614,8 @@ which incur interpreter overhead.
return imap(function, count(start)) return imap(function, count(start))
def nth(iterable, n): def nth(iterable, n):
"Returns the nth item or empty list" "Returns the nth item or None"
return list(islice(iterable, n, n+1)) return next(islice(iterable, n, None), None)
def quantify(iterable, pred=bool): def quantify(iterable, pred=bool):
"Count how many times the predicate is true" "Count how many times the predicate is true"

9
Lib/test/test_itertools.py
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@ -1201,8 +1201,8 @@ Samuele
... return imap(function, count(start)) ... return imap(function, count(start))
>>> def nth(iterable, n): >>> def nth(iterable, n):
... "Returns the nth item or empty list" ... "Returns the nth item or None"
... return list(islice(iterable, n, n+1)) ... return next(islice(iterable, n, None), None)
>>> def quantify(iterable, pred=bool): >>> def quantify(iterable, pred=bool):
... "Count how many times the predicate is true" ... "Count how many times the predicate is true"
@ -1318,7 +1318,10 @@ perform as purported.
[0, 2, 4, 6] [0, 2, 4, 6]
>>> nth('abcde', 3) >>> nth('abcde', 3)
['d'] 'd'
>>> nth('abcde', 9) is None
True
>>> quantify(xrange(99), lambda x: x%2==0) >>> quantify(xrange(99), lambda x: x%2==0)
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