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Issue #10912: add clarification for PyObject_RichCompareBool comparing identical objects

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Eli Bendersky 2011-04-30 08:51:55 +03:00
parent bb23bd69b9
commit 11d1171ecf
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Doc/c-api/object.rst
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@ -108,6 +108,9 @@ Object Protocol
Python expression ``o1 op o2``, where ``op`` is the operator corresponding to
*opid*.
.. note::
If *o1* and *o2* are the same object, :c:func:`PyObject_RichCompareBool`
will always return ``1`` for :const:`Py_EQ` and ``0`` for :const:`Py_NE`.
.. cfunction:: int PyObject_Cmp(PyObject *o1, PyObject *o2, int *result)