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Issue #8498: In socket.accept(), allow to specify 0 as a backlog value in

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order to accept exactly one connection.  Patch by Daniel Evers.
This commit is contained in:
Antoine Pitrou 2011-05-10 19:16:29 +02:00
parent cda41d3bf7
commit 1be815aac4
5 changed files with 20 additions and 6 deletions
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11
Modules/socketmodule.c
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@ -2220,8 +2220,10 @@ sock_listen(PySocketSockObject *s, PyObject *arg)
if (backlog == -1 && PyErr_Occurred())
return NULL;
Py_BEGIN_ALLOW_THREADS
if (backlog < 1)
backlog = 1;
/* To avoid problems on systems that don't allow a negative backlog
* (which doesn't make sense anyway) we force a minimum value of 0. */
if (backlog < 0)
backlog = 0;
res = listen(s->sock_fd, backlog);
Py_END_ALLOW_THREADS
if (res < 0)
@ -2234,8 +2236,9 @@ PyDoc_STRVAR(listen_doc,
"listen(backlog)\n\
\n\
Enable a server to accept connections. The backlog argument must be at\n\
least 1; it specifies the number of unaccepted connection that the system\n\
will allow before refusing new connections.");
least 0 (if it is lower, it is set to 0); it specifies the number of\n\
unaccepted connections that the system will allow before refusing new\n\
connections.");
/*