Issue #6561: '\d' in a regular expression should match only Unicode

character category [Nd],  not [No].
This commit is contained in:
Mark Dickinson 2009-07-28 17:22:36 +00:00
parent 6bd13fbbc8
commit 1f268285ff
4 changed files with 32 additions and 6 deletions

View file

@ -605,6 +605,27 @@ class ReTests(unittest.TestCase):
self.assertEqual(next(iter).span(), (4, 4))
self.assertRaises(StopIteration, next, iter)
def test_bug_6561(self):
# '\d' should match characters in Unicode category 'Nd'
# (Number, Decimal Digit), but not those in 'Nl' (Number,
# Letter) or 'No' (Number, Other).
decimal_digits = [
'\u0037', # '\N{DIGIT SEVEN}', category 'Nd'
'\u0e58', # '\N{THAI DIGIT SIX}', category 'Nd'
'\uff10', # '\N{FULLWIDTH DIGIT ZERO}', category 'Nd'
]
for x in decimal_digits:
self.assertEqual(re.match('^\d$', x).group(0), x)
not_decimal_digits = [
'\u2165', # '\N{ROMAN NUMERAL SIX}', category 'Nl'
'\u3039', # '\N{HANGZHOU NUMERAL TWENTY}', category 'Nl'
'\u2082', # '\N{SUBSCRIPT TWO}', category 'No'
'\u32b4', # '\N{CIRCLED NUMBER THIRTY NINE}', category 'No'
]
for x in not_decimal_digits:
self.assertIsNone(re.match('^\d$', x))
def test_empty_array(self):
# SF buf 1647541
import array