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r81522 | r.david.murray | 2010-05-25 11:36:46 -0400 (Tue, 25 May 2010) | 9 lines
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r81521 | r.david.murray | 2010-05-25 11:32:06 -0400 (Tue, 25 May 2010) | 2 lines
Issue 8818: urlparse/urlsplit keyword is 'scheme', not 'default_scheme'.
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@ -26,7 +26,7 @@ following URL schemes: ``file``, ``ftp``, ``gopher``, ``hdl``, ``http``,
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The :mod:`urllib.parse` module defines the following functions:
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.. function:: urlparse(urlstring, default_scheme='', allow_fragments=True)
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.. function:: urlparse(urlstring, scheme='', allow_fragments=True)
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Parse a URL into six components, returning a 6-tuple. This corresponds to the
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general structure of a URL: ``scheme://netloc/path;parameters?query#fragment``.
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@ -48,7 +48,7 @@ The :mod:`urllib.parse` module defines the following functions:
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>>> o.geturl()
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'http://www.cwi.nl:80/%7Eguido/Python.html'
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If the *default_scheme* argument is specified, it gives the default addressing
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If the *scheme* argument is specified, it gives the default addressing
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scheme, to be used only if the URL does not specify one. The default value for
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this argument is the empty string.
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@ -139,7 +139,7 @@ The :mod:`urllib.parse` module defines the following functions:
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states that these are equivalent).
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.. function:: urlsplit(urlstring, default_scheme='', allow_fragments=True)
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.. function:: urlsplit(urlstring, scheme='', allow_fragments=True)
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This is similar to :func:`urlparse`, but does not split the params from the URL.
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This should generally be used instead of :func:`urlparse` if the more recent URL
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