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Run 2to3 over Doc/lib/sqlite3/.

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This commit is contained in:
Collin Winter 2007-08-07 01:20:21 +00:00
parent b942d28bf5
commit 45d569b823
22 changed files with 43 additions and 43 deletions
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10
Doc/lib/sqlite3/text_factory.py
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@ -6,7 +6,7 @@ cur = con.cursor()
# Create the table
con.execute("create table person(lastname, firstname)")
AUSTRIA = u"\xd6sterreich"
AUSTRIA = "\xd6sterreich"
# by default, rows are returned as Unicode
cur.execute("select ?", (AUSTRIA,))
@ -25,17 +25,17 @@ assert row[0] == AUSTRIA.encode("utf-8")
# we can also implement a custom text_factory ...
# here we implement one that will ignore Unicode characters that cannot be
# decoded from UTF-8
con.text_factory = lambda x: unicode(x, "utf-8", "ignore")
cur.execute("select ?", ("this is latin1 and would normally create errors" + u"\xe4\xf6\xfc".encode("latin1"),))
con.text_factory = lambda x: str(x, "utf-8", "ignore")
cur.execute("select ?", ("this is latin1 and would normally create errors" + "\xe4\xf6\xfc".encode("latin1"),))
row = cur.fetchone()
assert type(row[0]) == unicode
assert type(row[0]) == str
# pysqlite offers a builtin optimized text_factory that will return bytestring
# objects, if the data is in ASCII only, and otherwise return unicode objects
con.text_factory = sqlite3.OptimizedUnicode
cur.execute("select ?", (AUSTRIA,))
row = cur.fetchone()
assert type(row[0]) == unicode
assert type(row[0]) == str
cur.execute("select ?", ("Germany",))
row = cur.fetchone()