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keep the slice.step field as NULL if no step expression is given
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3 changed files with 10 additions and 8 deletions
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@ -146,6 +146,12 @@ class AST_Tests(unittest.TestCase):
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self.assertEquals(to_tuple(ast_tree), o)
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self._assert_order(ast_tree, (0, 0))
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def test_slice(self):
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slc = ast.parse("x[::]").body[0].value.slice
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self.assertIsNone(slc.upper)
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self.assertIsNone(slc.lower)
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self.assertIsNone(slc.step)
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def test_nodeclasses(self):
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x = ast.BinOp(1, 2, 3, lineno=0)
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self.assertEquals(x.left, 1)
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@ -12,6 +12,9 @@ What's New in Python 2.7 alpha 1
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Core and Builtins
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-----------------
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- In the slice AST type, the step field will always be None if a step expression
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is not specified.
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- Issue #4547: When debugging a very large function, it was not always
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possible to update the lineno attribute of the current frame.
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@ -1468,14 +1468,7 @@ ast_for_slice(struct compiling *c, const node *n)
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ch = CHILD(n, NCH(n) - 1);
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if (TYPE(ch) == sliceop) {
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if (NCH(ch) == 1) {
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/* No expression, so step is None */
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ch = CHILD(ch, 0);
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step = Name(new_identifier("None", c->c_arena), Load,
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LINENO(ch), ch->n_col_offset, c->c_arena);
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if (!step)
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return NULL;
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} else {
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if (NCH(ch) != 1) {
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ch = CHILD(ch, 1);
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if (TYPE(ch) == test) {
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step = ast_for_expr(c, ch);
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