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bpo-27657: Fix urlparse() with numeric paths (#661)

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* bpo-27657: Fix urlparse() with numeric paths

Revert parsing decision from bpo-754016 in favor of the documented
consensus in bpo-16932 of how to treat strings without a // to
designate the netloc.

* bpo-22891: Remove urlsplit() optimization for 'http' prefixed inputs.
This commit is contained in:
Tim Graham 2019-10-18 09:07:20 -04:00 • committed by Senthil Kumaran
parent fbe3c76c7c
commit 5a88d50ff0
3 changed files with 9 additions and 25 deletions
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22
Lib/urllib/parse.py
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@ -431,31 +431,11 @@ def urlsplit(url, scheme='', allow_fragments=True):
netloc = query = fragment = ''
i = url.find(':')
if i > 0:
if url[:i] == 'http': # optimize the common case
url = url[i+1:]
if url[:2] == '//':
netloc, url = _splitnetloc(url, 2)
if (('[' in netloc and ']' not in netloc) or
(']' in netloc and '[' not in netloc)):
raise ValueError("Invalid IPv6 URL")
if allow_fragments and '#' in url:
url, fragment = url.split('#', 1)
if '?' in url:
url, query = url.split('?', 1)
_checknetloc(netloc)
v = SplitResult('http', netloc, url, query, fragment)
_parse_cache[key] = v
return _coerce_result(v)
for c in url[:i]:
if c not in scheme_chars:
break
else:
# make sure "url" is not actually a port number (in which case
# "scheme" is really part of the path)
rest = url[i+1:]
if not rest or any(c not in '0123456789' for c in rest):
# not a port number
scheme, url = url[:i].lower(), rest
scheme, url = url[:i].lower(), url[i+1:]
if url[:2] == '//':
netloc, url = _splitnetloc(url, 2)