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Issue #28959: Added private macro PyDict_GET_SIZE for retrieving the size of dict.

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This commit is contained in:
Serhiy Storchaka 2016-12-16 16:18:57 +02:00
parent 1d59a0aacf
commit 5ab81d787f
25 changed files with 61 additions and 80 deletions
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6
Python/getargs.c
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@ -1650,7 +1650,7 @@ vgetargskeywords(PyObject *args, PyObject *keywords, const char *format,
}
nargs = PyTuple_GET_SIZE(args);
nkeywords = (keywords == NULL) ? 0 : PyDict_Size(keywords);
nkeywords = (keywords == NULL) ? 0 : PyDict_GET_SIZE(keywords);
if (nargs + nkeywords > len) {
PyErr_Format(PyExc_TypeError,
"%s%s takes at most %d argument%s (%zd given)",
@ -2034,7 +2034,7 @@ vgetargskeywordsfast_impl(PyObject **args, Py_ssize_t nargs,
}
if (keywords != NULL) {
nkeywords = PyDict_Size(keywords);
nkeywords = PyDict_GET_SIZE(keywords);
}
else if (kwnames != NULL) {
nkeywords = PyTuple_GET_SIZE(kwnames);
@ -2421,7 +2421,7 @@ _PyArg_NoKeywords(const char *funcname, PyObject *kw)
PyErr_BadInternalCall();
return 0;
}
if (PyDict_Size(kw) == 0)
if (PyDict_GET_SIZE(kw) == 0)
return 1;
PyErr_Format(PyExc_TypeError, "%s does not take keyword arguments",