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gh-133889: Only show the path of the URL in the SimpleHTTPRequestHandler page (GH-134135)

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The query and fragment are ambiguous and not used.
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Serhiy Storchaka 2025-05-18 21:09:51 +03:00 • committed by GitHub
parent bb32f3c698
commit 5cbc8c632e
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3 changed files with 15 additions and 8 deletions
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7
Lib/http/server.py
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@ -818,11 +818,14 @@ class SimpleHTTPRequestHandler(BaseHTTPRequestHandler):
return None
list.sort(key=lambda a: a.lower())
r = []
displaypath = self.path
displaypath = displaypath.split('#', 1)[0]
displaypath = displaypath.split('?', 1)[0]
try:
displaypath = urllib.parse.unquote(self.path,
displaypath = urllib.parse.unquote(displaypath,
errors='surrogatepass')
except UnicodeDecodeError:
displaypath = urllib.parse.unquote(self.path)
displaypath = urllib.parse.unquote(displaypath)
displaypath = html.escape(displaypath, quote=False)
enc = sys.getfilesystemencoding()
title = f'Directory listing for {displaypath}'