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bpo-44019: Implement operator.call(). (GH-27888)

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Having `operator.call(obj, arg)` mean `type(obj).__call__(obj, arg)` is
consistent with the other dunder operators.  The semantics with `*args,
**kwargs` then follow naturally from the single-arg semantics.
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Antony Lee 2021-09-24 17:22:49 +02:00 • committed by GitHub
parent 8d8729146f
commit 6587fc60d4
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12
Lib/test/test_operator.py
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@ -518,6 +518,18 @@ class OperatorTestCase:
with self.assertRaises(LookupError):
operator.length_hint(X(LookupError))
def test_call(self):
operator = self.module
def func(*args, **kwargs): return args, kwargs
self.assertEqual(operator.call(func), ((), {}))
self.assertEqual(operator.call(func, 0, 1), ((0, 1), {}))
self.assertEqual(operator.call(func, a=2, obj=3),
((), {"a": 2, "obj": 3}))
self.assertEqual(operator.call(func, 0, 1, a=2, obj=3),
((0, 1), {"a": 2, "obj": 3}))
def test_dunder_is_original(self):
operator = self.module