Issue #21566: Make use of socket.listen() default backlog.

This commit is contained in:
Charles-François Natali 2014-07-23 19:28:13 +01:00
parent 8518b79a8d
commit 6e20460dc6
18 changed files with 33 additions and 33 deletions

View file

@ -1211,7 +1211,7 @@ class SSLErrorTests(unittest.TestCase):
ctx = ssl.SSLContext(ssl.PROTOCOL_TLSv1)
with socket.socket() as s:
s.bind(("127.0.0.1", 0))
s.listen(5)
s.listen()
c = socket.socket()
c.connect(s.getsockname())
c.setblocking(False)
@ -1736,7 +1736,7 @@ else:
def run(self):
self.sock.settimeout(0.05)
self.sock.listen(5)
self.sock.listen()
self.active = True
if self.flag:
# signal an event
@ -2162,7 +2162,7 @@ else:
# and sets Event `listener_gone` to let the main thread know
# the socket is gone.
def listener():
s.listen(5)
s.listen()
listener_ready.set()
newsock, addr = s.accept()
newsock.close()
@ -2590,7 +2590,7 @@ else:
finish = False
def serve():
server.listen(5)
server.listen()
started.set()
conns = []
while not finish:
@ -2647,7 +2647,7 @@ else:
peer = None
def serve():
nonlocal remote, peer
server.listen(5)
server.listen()
# Block on the accept and wait on the connection to close.
evt.set()
remote, peer = server.accept()