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Fix Issue754016 - urlparse goes wrong with IP:port without scheme

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Senthil Kumaran 2010-08-04 04:50:44 +00:00
parent 4aa0d4d2d0
commit 84c7d9f87b
3 changed files with 44 additions and 5 deletions
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17
Doc/library/urllib.parse.rst
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@ -48,6 +48,23 @@ The :mod:`urllib.parse` module defines the following functions:
>>> o.geturl()
'http://www.cwi.nl:80/%7Eguido/Python.html'
If the scheme value is not specified, urlparse following the syntax
specifications from RFC 1808, expects the netloc value to start with '//',
Otherwise, it is not possible to distinguish between net_loc and path
component and would classify the indistinguishable component as path as in
a relative url.
>>> from urlparse import urlparse
>>> urlparse('//www.cwi.nl:80/%7Eguido/Python.html')
ParseResult(scheme='', netloc='www.cwi.nl:80', path='/%7Eguido/Python.html',
params='', query='', fragment='')
>>> urlparse('www.cwi.nl:80/%7Eguido/Python.html')
ParseResult(scheme='', netloc='', path='www.cwi.nl:80/%7Eguido/Python.html',
params='', query='', fragment='')
>>> urlparse('help/Python.html')
ParseResult(scheme='', netloc='', path='help/Python.html', params='',
query='', fragment='')
If the *scheme* argument is specified, it gives the default addressing
scheme, to be used only if the URL does not specify one. The default value for
this argument is the empty string.