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Separate CFLAGS and CPPFLAGS. CFLAGS should not contain preprocessor

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directives, which is the role of CPPFLAGS.  Closes SF patch #414991.
This commit is contained in:
Neil Schemenauer 2001-06-02 06:16:02 +00:00
parent f4b33f61fb
commit 89e90d67aa
7 changed files with 19 additions and 12 deletions
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4
Tools/freeze/freeze.py
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@ -424,7 +424,8 @@ def main():
outfp.close()
infp.close()
cflags = defines + includes + ['$(OPT)']
cflags = ['$(OPT)']
cppflags = defines + includes
libs = [os.path.join(binlib, 'libpython$(VERSION).a')]
somevars = {}
@ -434,6 +435,7 @@ def main():
somevars[key] = makevars[key]
somevars['CFLAGS'] = string.join(cflags) # override
somevars['CPPFLAGS'] = string.join(cppflags) # override
files = ['$(OPT)', '$(LDFLAGS)', base_config_c, base_frozen_c] + \
files + supp_sources + addfiles + libs + \
['$(MODLIBS)', '$(LIBS)', '$(SYSLIBS)']

2
Tools/freeze/makemakefile.py
View file

@ -19,7 +19,7 @@ def makemakefile(outfp, makevars, files, target):
base = os.path.basename(file)
dest = base[:-2] + '.o'
outfp.write("%s: %s\n" % (dest, file))
outfp.write("\t$(CC) $(CFLAGS) -c %s\n" % file)
outfp.write("\t$(CC) $(CFLAGS) $(CPPFLAGS) -c %s\n" % file)
files[i] = dest
deps.append(dest)