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Make 'as' an actual keyword when with's future statement is used. Not

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actually necessary for functionality, but good for transition.
This commit is contained in:
Thomas Wouters 2006-02-28 22:42:15 +00:00
parent 6cba25666c
commit 8ae1295c5b
5 changed files with 212 additions and 206 deletions
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22
Parser/parser.c
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@ -144,18 +144,20 @@ classify(parser_state *ps, int type, char *str)
register label *l = g->g_ll.ll_label;
register int i;
for (i = n; i > 0; i--, l++) {
if (l->lb_type == NAME && l->lb_str != NULL &&
l->lb_str[0] == s[0] &&
strcmp(l->lb_str, s) == 0) {
if (l->lb_type != NAME || l->lb_str == NULL ||
l->lb_str[0] != s[0] ||
strcmp(l->lb_str, s) != 0)
continue;
#ifdef PY_PARSER_REQUIRES_FUTURE_KEYWORD
if (!(ps->p_flags & CO_FUTURE_WITH_STATEMENT) &&
s[0] == 'w' &&
strcmp(s, "with") == 0)
break; /* not a keyword */
#endif
D(printf("It's a keyword\n"));
return n - i;
if (!(ps->p_flags & CO_FUTURE_WITH_STATEMENT)) {
if (s[0] == 'w' && strcmp(s, "with") == 0)
break; /* not a keyword yet */
else if (s[0] == 'a' && strcmp(s, "as") == 0)
break; /* not a keyword yet */
}
#endif
D(printf("It's a keyword\n"));
return n - i;
}
}