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improve the command-line interface of json.tool (closes #21000)

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A patch from Berker Peksag.
This commit is contained in:
Benjamin Peterson 2014-03-21 23:17:29 -05:00
parent a191b91a43
commit 940e207412
4 changed files with 76 additions and 12 deletions
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27
Lib/json/tool.py
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@ -10,21 +10,24 @@ Usage::
Expecting property name enclosed in double quotes: line 1 column 3 (char 2)
"""
import sys
import argparse
import json
import sys
def main():
if len(sys.argv) == 1:
infile = sys.stdin
outfile = sys.stdout
elif len(sys.argv) == 2:
infile = open(sys.argv[1], 'r')
outfile = sys.stdout
elif len(sys.argv) == 3:
infile = open(sys.argv[1], 'r')
outfile = open(sys.argv[2], 'w')
else:
raise SystemExit(sys.argv[0] + " [infile [outfile]]")
prog = 'python -m json.tool'
description = ('A simple command line interface for json module '
'to validate and pretty-print JSON objects.')
parser = argparse.ArgumentParser(prog=prog, description=description)
parser.add_argument('infile', nargs='?', type=argparse.FileType(),
help='a JSON file to be validated or pretty-printed')
parser.add_argument('outfile', nargs='?', type=argparse.FileType('w'),
help='write the output of infile to outfile')
options = parser.parse_args()
infile = options.infile or sys.stdin
outfile = options.outfile or sys.stdout
with infile:
try:
obj = json.load(infile)