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[3.13] gh-121905: Consistently use "floating-point" instead of "floating point" (GH-121907) (GH-122012)

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(cherry picked from commit 1a0c7b9ba4)
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Serhiy Storchaka 2024-07-19 12:13:08 +03:00 • committed by GitHub
parent 225cbee8d8
commit a45d9051ed
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100 changed files with 238 additions and 238 deletions
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14
Modules/mathmodule.c
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@ -107,7 +107,7 @@ typedef struct{ double hi; double lo; } DoubleLength;
static DoubleLength
dl_fast_sum(double a, double b)
{
/* Algorithm 1.1. Compensated summation of two floating point numbers. */
/* Algorithm 1.1. Compensated summation of two floating-point numbers. */
assert(fabs(a) >= fabs(b));
double x = a + b;
double y = (a - x) + b;
@ -1354,14 +1354,14 @@ math.fsum
seq: object
/
Return an accurate floating point sum of values in the iterable seq.
Return an accurate floating-point sum of values in the iterable seq.
Assumes IEEE-754 floating point arithmetic.
Assumes IEEE-754 floating-point arithmetic.
[clinic start generated code]*/
static PyObject *
math_fsum(PyObject *module, PyObject *seq)
/*[clinic end generated code: output=ba5c672b87fe34fc input=c51b7d8caf6f6e82]*/
/*[clinic end generated code: output=ba5c672b87fe34fc input=4506244ded6057dc]*/
{
PyObject *item, *iter, *sum = NULL;
Py_ssize_t i, j, n = 0, m = NUM_PARTIALS;
@ -2453,7 +2453,7 @@ Since lo**2 is less than 1/2 ulp(csum), we have csum+lo*lo == csum.
To minimize loss of information during the accumulation of fractional
values, each term has a separate accumulator. This also breaks up
sequential dependencies in the inner loop so the CPU can maximize
floating point throughput. [4] On an Apple M1 Max, hypot(*vec)
floating-point throughput. [4] On an Apple M1 Max, hypot(*vec)
takes only 3.33 µsec when len(vec) == 1000.
The square root differential correction is needed because a
@ -3136,7 +3136,7 @@ math.isclose -> bool
maximum difference for being considered "close", regardless of the
magnitude of the input values
Determine whether two floating point numbers are close in value.
Determine whether two floating-point numbers are close in value.
Return True if a is close in value to b, and False otherwise.
@ -3151,7 +3151,7 @@ only close to themselves.
static int
math_isclose_impl(PyObject *module, double a, double b, double rel_tol,
double abs_tol)
/*[clinic end generated code: output=b73070207511952d input=f28671871ea5bfba]*/
/*[clinic end generated code: output=b73070207511952d input=12d41764468bfdb8]*/
{
double diff = 0.0;