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(sched) when run() is invoked with blocking=False return the deadline of the next scheduled call in the scheduler; this use case was suggested in http://bugs.python.org/issue1641#msg149453
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2 changed files with 5 additions and 3 deletions
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@ -97,7 +97,8 @@ class scheduler:
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def run(self, blocking=True):
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"""Execute events until the queue is empty.
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If blocking is False executes the scheduled events due to
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expire soonest (if any) and then return.
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expire soonest (if any) and then return the deadline of the
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next scheduled call in the scheduler.
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When there is a positive delay until the first event, the
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delay function is called and the event is left in the queue;
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@ -129,7 +130,7 @@ class scheduler:
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now = timefunc()
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if now < time:
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if not blocking:
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return
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return time - now
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delayfunc(time - now)
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else:
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event = pop(q)
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