mirrors/cpython
1
0
Fork 0
mirror of https://github.com/python/cpython.git synced 2025-09-17 14:16:02 +00:00
Code Issues Projects Releases Packages Wiki Activity Actions 8

Fix issue 2522. locale.format now checks that it is passed

Browse source 
exactly one pattern, which avoids mysterious errors where it
had seemed to fail to do localization.
This commit is contained in:
R. David Murray 2009-04-01 03:21:43 +00:00
parent bb94d43dcd
commit a83da3507f
4 changed files with 35 additions and 8 deletions
Download patch file Download diff file Expand all files Collapse all files

23
Lib/locale.py
View file

@ -11,7 +11,11 @@
"""
import sys, encodings, encodings.aliases
import sys
import encodings
import encodings.aliases
import re
import operator
import functools
# Try importing the _locale module.
@ -166,6 +170,9 @@ def _strip_padding(s, amount):
amount -= 1
return s[lpos:rpos+1]
_percent_re = re.compile(r'%(?:\((?P<key>.*?)\))?'
r'(?P<modifiers>[-#0-9 +*.hlL]*?)[eEfFgGdiouxXcrs%]')
def format(percent, value, grouping=False, monetary=False, *additional):
"""Returns the locale-aware substitution of a %? specifier
(percent).
@ -173,9 +180,13 @@ def format(percent, value, grouping=False, monetary=False, *additional):
additional is for format strings which contain one or more
'*' modifiers."""
# this is only for one-percent-specifier strings and this should be checked
if percent[0] != '%':
raise ValueError("format() must be given exactly one %char "
"format specifier")
match = _percent_re.match(percent)
if not match or len(match.group())!= len(percent):
raise ValueError(("format() must be given exactly one %%char "
"format specifier, %s not valid") % repr(percent))
return _format(percent, value, grouping, monetary, *additional)
def _format(percent, value, grouping=False, monetary=False, *additional):
if additional:
formatted = percent % ((value,) + additional)
else:
@ -199,10 +210,6 @@ def format(percent, value, grouping=False, monetary=False, *additional):
formatted = _strip_padding(formatted, seps)
return formatted
import re, operator
_percent_re = re.compile(r'%(?:\((?P<key>.*?)\))?'
r'(?P<modifiers>[-#0-9 +*.hlL]*?)[eEfFgGdiouxXcrs%]')
def format_string(f, val, grouping=False):
"""Formats a string in the same way that the % formatting would use,
but takes the current locale into account.