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SF bug #436207: "if 0: yield x" is ignored.

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Not anymore <wink>.  Pure hack.  Doesn't fix any other "if 0:" glitches.
This commit is contained in:
Tim Peters 2001-06-26 03:36:28 +00:00
parent 3e7b1a04a0
commit b6c3ceae79
2 changed files with 161 additions and 8 deletions
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34
Python/compile.c
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@ -4840,6 +4840,34 @@ symtable_add_def_o(struct symtable *st, PyObject *dict,
#define symtable_add_use(ST, NAME) symtable_add_def((ST), (NAME), USE)
/* Look for a yield stmt under n. Return 1 if found, else 0. */
static int
look_for_yield(node *n)
{
int i;
for (i = 0; i < NCH(n); ++i) {
node *kid = CHILD(n, i);
switch (TYPE(kid)) {
case classdef:
case funcdef:
/* Stuff in nested functions and classes can't make
the parent a generator. */
return 0;
case yield_stmt:
return 1;
default:
if (look_for_yield(kid))
return 1;
}
}
return 0;
}
static void
symtable_node(struct symtable *st, node *n)
{
@ -4883,8 +4911,12 @@ symtable_node(struct symtable *st, node *n)
}
case if_stmt:
for (i = 0; i + 3 < NCH(n); i += 4) {
if (is_constant_false(NULL, (CHILD(n, i + 1))))
if (is_constant_false(NULL, (CHILD(n, i + 1)))) {
if (st->st_cur->ste_generator == 0)
st->st_cur->ste_generator =
look_for_yield(CHILD(n, i+3));
continue;
}
symtable_node(st, CHILD(n, i + 1));
symtable_node(st, CHILD(n, i + 3));
}