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Fixed AttributeError when the regular expression starts from illegal escape.

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Serhiy Storchaka 2014-11-10 14:38:16 +02:00
parent ce40e1a081
commit b99c132bd9
2 changed files with 15 additions and 0 deletions
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14
Lib/test/test_re.py
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@ -531,6 +531,20 @@ class ReTests(unittest.TestCase):
self.assertEqual(re.search(br"\d\D\w\W\s\S",
b"1aa! a", re.LOCALE).group(0), b"1aa! a")
def test_other_escapes(self):
self.assertRaises(re.error, re.compile, "\\")
self.assertEqual(re.match(r"\(", '(').group(), '(')
self.assertIsNone(re.match(r"\(", ')'))
self.assertEqual(re.match(r"\\", '\\').group(), '\\')
self.assertEqual(re.match(r"\y", 'y').group(), 'y')
self.assertIsNone(re.match(r"\y", 'z'))
self.assertEqual(re.match(r"[\]]", ']').group(), ']')
self.assertIsNone(re.match(r"[\]]", '['))
self.assertEqual(re.match(r"[a\-c]", '-').group(), '-')
self.assertIsNone(re.match(r"[a\-c]", 'b'))
self.assertEqual(re.match(r"[\^a]+", 'a^').group(), 'a^')
self.assertIsNone(re.match(r"[\^a]+", 'b'))
def test_string_boundaries(self):
# See http://bugs.python.org/issue10713
self.assertEqual(re.search(r"\b(abc)\b", "abc").group(1),