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Code Issues Projects Releases Packages Wiki Activity Actions 9

Remove to-be-deprecated urllib.request.urlretrieve function reference (#6454)

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Andrés Delfino 2018-04-16 11:02:56 -03:00 • committed by Senthil Kumaran
parent b8e21f1289
commit c89b221758
1 changed files with 12 additions and 4 deletions
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16
Doc/howto/urllib2.rst
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@ -56,12 +56,20 @@ The simplest way to use urllib.request is as follows::
with urllib.request.urlopen('http://python.org/') as response: with urllib.request.urlopen('http://python.org/') as response:
html = response.read() html = response.read()
If you wish to retrieve a resource via URL and store it in a temporary location, If you wish to retrieve a resource via URL and store it in a temporary
you can do so via the :func:`~urllib.request.urlretrieve` function:: location, you can do so via the :func:`shutil.copyfileobj` and
:func:`tempfile.NamedTemporaryFile` functions::
import shutil
import tempfile
import urllib.request import urllib.request
local_filename, headers = urllib.request.urlretrieve('http://python.org/')
html = open(local_filename) with urllib.request.urlopen('http://python.org/') as response:
with tempfile.NamedTemporaryFile(delete=False) as tmp_file:
shutil.copyfileobj(response, tmp_file)
with open(tmp_file.name) as html:
pass
Many uses of urllib will be that simple (note that instead of an 'http:' URL we Many uses of urllib will be that simple (note that instead of an 'http:' URL we
could have used a URL starting with 'ftp:', 'file:', etc.). However, it's the could have used a URL starting with 'ftp:', 'file:', etc.). However, it's the