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Issue #20426: When passing the re.DEBUG flag, re.compile() displays the debug output every time it is called, regardless of the compilation cache.

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This commit is contained in:
Antoine Pitrou 2014-02-03 20:59:59 +01:00
parent b3de1a720a
commit d2cc743ca4
3 changed files with 27 additions and 8 deletions
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17
Lib/re.py
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@ -267,10 +267,12 @@ _pattern_type = type(sre_compile.compile("", 0))
_MAXCACHE = 512
def _compile(pattern, flags):
# internal: compile pattern
try:
return _cache[type(pattern), pattern, flags]
except KeyError:
pass
bypass_cache = flags & DEBUG
if not bypass_cache:
try:
return _cache[type(pattern), pattern, flags]
except KeyError:
pass
if isinstance(pattern, _pattern_type):
if flags:
raise ValueError(
@ -279,9 +281,10 @@ def _compile(pattern, flags):
if not sre_compile.isstring(pattern):
raise TypeError("first argument must be string or compiled pattern")
p = sre_compile.compile(pattern, flags)
if len(_cache) >= _MAXCACHE:
_cache.clear()
_cache[type(pattern), pattern, flags] = p
if not bypass_cache:
if len(_cache) >= _MAXCACHE:
_cache.clear()
_cache[type(pattern), pattern, flags] = p
return p
def _compile_repl(repl, pattern):