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Issue #27076: More doc and comment spelling fixes for 3.6, by Ville Skyttä
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4 changed files with 5 additions and 5 deletions
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@ -2079,7 +2079,7 @@ Notes:
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Similar to ``%U`` and ``%W``, ``%V`` is only used in calculations when the
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Similar to ``%U`` and ``%W``, ``%V`` is only used in calculations when the
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day of the week and the ISO year (``%G``) are specified in a
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day of the week and the ISO year (``%G``) are specified in a
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:meth:`strptime` format string. Also note that ``%G`` and ``%Y`` are not
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:meth:`strptime` format string. Also note that ``%G`` and ``%Y`` are not
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interchangable.
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interchangeable.
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.. rubric:: Footnotes
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.. rubric:: Footnotes
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@ -507,7 +507,7 @@ An :class:`IMAP4` instance has the following methods:
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allowed creation of such tags, and popular IMAP servers, such as Gmail,
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allowed creation of such tags, and popular IMAP servers, such as Gmail,
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accept and produce such flags. There are non-Python programs which also
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accept and produce such flags. There are non-Python programs which also
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create such tags. Although it is an RFC violation and IMAP clients and
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create such tags. Although it is an RFC violation and IMAP clients and
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servers are supposed to be strict, imaplib nontheless continues to allow
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servers are supposed to be strict, imaplib nonetheless continues to allow
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such tags to be created for backward compatibility reasons, and as of
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such tags to be created for backward compatibility reasons, and as of
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python 3.6, handles them if they are sent from the server, since this
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python 3.6, handles them if they are sent from the server, since this
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improves real-world compatibility.
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improves real-world compatibility.
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@ -430,9 +430,9 @@ def median_grouped(data, interval=1):
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L = float(x) - float(interval)/2
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L = float(x) - float(interval)/2
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# Uses bisection search to search for x in data with log(n) time complexity
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# Uses bisection search to search for x in data with log(n) time complexity
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# Find the position of leftmost occurence of x in data
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# Find the position of leftmost occurrence of x in data
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l1 = _find_lteq(data, x)
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l1 = _find_lteq(data, x)
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# Find the position of rightmost occurence of x in data[l1...len(data)]
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# Find the position of rightmost occurrence of x in data[l1...len(data)]
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# Assuming always l1 <= l2
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# Assuming always l1 <= l2
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l2 = _find_rteq(data, l1, x)
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l2 = _find_rteq(data, l1, x)
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cf = l1
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cf = l1
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@ -635,7 +635,7 @@ class TestBasicOps(unittest.TestCase):
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# Mode 0 is efficient. It uses an incompletely consumed input
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# Mode 0 is efficient. It uses an incompletely consumed input
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# iterator to build a cycle object and then passes in state with
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# iterator to build a cycle object and then passes in state with
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# a list of previously consumed values. There is no data
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# a list of previously consumed values. There is no data
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# overlap bewteen the two.
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# overlap between the two.
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c = cycle('defg')
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c = cycle('defg')
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c.__setstate__((list('abc'), 0))
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c.__setstate__((list('abc'), 0))
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self.assertEqual(take(20, c), list('defgabcdefgabcdefgab'))
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self.assertEqual(take(20, c), list('defgabcdefgabcdefgab'))
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