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Clean-up itertools docs and recipes.

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Raymond Hettinger 2008-07-19 23:58:47 +00:00
parent 39e0eb766f
commit f1f46f0350
2 changed files with 33 additions and 98 deletions
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70
Lib/test/test_itertools.py
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@ -1185,52 +1185,32 @@ Samuele
[22]
[25, 26, 27, 28]
>>> def take(n, seq):
... return list(islice(seq, n))
>>> def take(n, iterable):
... "Return first n items of the iterable as a list"
... return list(islice(iterable, n))
>>> def enumerate(iterable):
... return izip(count(), iterable)
>>> def enumerate(iterable, start=0):
... return izip(count(start), iterable)
>>> def tabulate(function):
>>> def tabulate(function, start=0):
... "Return function(0), function(1), ..."
... return imap(function, count())
>>> def iteritems(mapping):
... return izip(mapping.iterkeys(), mapping.itervalues())
... return imap(function, count(start))
>>> def nth(iterable, n):
... "Returns the nth item"
... "Returns the nth item or empty list"
... return list(islice(iterable, n, n+1))
>>> def all(seq, pred=None):
... "Returns True if pred(x) is true for every element in the iterable"
... for elem in ifilterfalse(pred, seq):
... return False
... return True
>>> def quantify(iterable, pred=bool):
... "Count how many times the predicate is true"
... return sum(imap(pred, iterable))
>>> def any(seq, pred=None):
... "Returns True if pred(x) is true for at least one element in the iterable"
... for elem in ifilter(pred, seq):
... return True
... return False
>>> def no(seq, pred=None):
... "Returns True if pred(x) is false for every element in the iterable"
... for elem in ifilter(pred, seq):
... return False
... return True
>>> def quantify(seq, pred=None):
... "Count how many times the predicate is true in the sequence"
... return sum(imap(pred, seq))
>>> def padnone(seq):
>>> def padnone(iterable):
... "Returns the sequence elements and then returns None indefinitely"
... return chain(seq, repeat(None))
... return chain(iterable, repeat(None))
>>> def ncycles(seq, n):
... "Returns the sequence elements n times"
... return chain(*repeat(seq, n))
>>> def ncycles(iterable, n):
... "Returns the seqeuence elements n times"
... return chain(*repeat(iterable, n))
>>> def dotproduct(vec1, vec2):
... return sum(imap(operator.mul, vec1, vec2))
@ -1315,24 +1295,6 @@ perform as purported.
>>> nth('abcde', 3)
['d']
>>> all([2, 4, 6, 8], lambda x: x%2==0)
True
>>> all([2, 3, 6, 8], lambda x: x%2==0)
False
>>> any([2, 4, 6, 8], lambda x: x%2==0)
True
>>> any([1, 3, 5, 9], lambda x: x%2==0,)
False
>>> no([1, 3, 5, 9], lambda x: x%2==0)
True
>>> no([1, 2, 5, 9], lambda x: x%2==0)
False
>>> quantify(xrange(99), lambda x: x%2==0)
50