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Use macro to get length of list.

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Remove comment about how code used to work.
This commit is contained in:
Jeremy Hylton 2003-05-22 16:22:33 +00:00
parent 521482d84f
commit f9415e6245
1 changed files with 2 additions and 8 deletions
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10
Python/compile.c
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@ -4967,15 +4967,9 @@ symtable_update_free_vars(struct symtable *st)
for (i = 0; i < PyList_GET_SIZE(ste->ste_children); ++i) { for (i = 0; i < PyList_GET_SIZE(ste->ste_children); ++i) {
int pos = 0; int pos = 0;
if (list) if (list && PyList_SetSlice(list, 0,
if (PyList_SetSlice(list, 0, PyList_GET_SIZE(list), 0) < 0)
((PyVarObject*)list)->ob_size, 0) < 0)
return -1; return -1;
/* Yes, the above call CAN fail, even though it's reducing
the size of the list. The current implementation will
allocate temp memory equal to the size of the list: this
is avoidable in this specific case, but probably not
worth the effort of special-casing it. - JRH */
child = (PySymtableEntryObject *) child = (PySymtableEntryObject *)
PyList_GET_ITEM(ste->ste_children, i); PyList_GET_ITEM(ste->ste_children, i);
while (PyDict_Next(child->ste_symbols, &pos, &name, &o)) { while (PyDict_Next(child->ste_symbols, &pos, &name, &o)) {