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Added a new macro, Py_IS_FINITE(X). On windows there is an intrinsic for this and it is more efficient than to use !Py_IS_INFINITE(X) && !Py_IS_NAN(X). No change on other platforms

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Kristján Valur Jónsson 2006-05-25 15:53:30 +00:00
parent 4b4e33ef14
commit f94323fbb4
3 changed files with 12 additions and 5 deletions
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7
Objects/floatobject.c
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@ -384,7 +384,7 @@ float_richcompare(PyObject *v, PyObject *w, int op)
if (PyFloat_Check(w))
j = PyFloat_AS_DOUBLE(w);
else if (Py_IS_INFINITY(i) || Py_IS_NAN(i)) {
else if (!Py_IS_FINITE(i)) {
if (PyInt_Check(w) || PyLong_Check(w))
/* If i is an infinity, its magnitude exceeds any
* finite integer, so it doesn't matter which int we
@ -802,10 +802,7 @@ float_pow(PyObject *v, PyObject *w, PyObject *z)
* bug; we let that slide in math.pow() (which currently
* reflects all platform accidents), but not for Python's **.
*/
if (iv == -1.0 && !Py_IS_INFINITY(iw) && iw == iw) {
/* XXX the "iw == iw" was to weed out NaNs. This
* XXX doesn't actually work on all platforms.
*/
if (iv == -1.0 && Py_IS_FINITE(iw)) {
/* Return 1 if iw is even, -1 if iw is odd; there's
* no guarantee that any C integral type is big
* enough to hold iw, so we have to check this