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			92 lines
		
	
	
	
		
			2.5 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
			
		
		
	
	
			92 lines
		
	
	
	
		
			2.5 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
| """Bisection algorithms."""
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| 
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| def insort_right(a, x, lo=0, hi=None):
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|     """Insert item x in list a, and keep it sorted assuming a is sorted.
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| 
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|     If x is already in a, insert it to the right of the rightmost x.
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| 
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|     Optional args lo (default 0) and hi (default len(a)) bound the
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|     slice of a to be searched.
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|     """
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| 
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|     if lo < 0:
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|         raise ValueError('lo must be non-negative')
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|     if hi is None:
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|         hi = len(a)
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|     while lo < hi:
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|         mid = (lo+hi)//2
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|         if x < a[mid]: hi = mid
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|         else: lo = mid+1
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|     a.insert(lo, x)
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| 
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| insort = insort_right   # backward compatibility
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| 
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| def bisect_right(a, x, lo=0, hi=None):
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|     """Return the index where to insert item x in list a, assuming a is sorted.
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| 
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|     The return value i is such that all e in a[:i] have e <= x, and all e in
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|     a[i:] have e > x.  So if x already appears in the list, a.insert(x) will
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|     insert just after the rightmost x already there.
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| 
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|     Optional args lo (default 0) and hi (default len(a)) bound the
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|     slice of a to be searched.
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|     """
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| 
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|     if lo < 0:
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|         raise ValueError('lo must be non-negative')
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|     if hi is None:
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|         hi = len(a)
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|     while lo < hi:
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|         mid = (lo+hi)//2
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|         if x < a[mid]: hi = mid
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|         else: lo = mid+1
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|     return lo
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| 
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| bisect = bisect_right   # backward compatibility
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| 
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| def insort_left(a, x, lo=0, hi=None):
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|     """Insert item x in list a, and keep it sorted assuming a is sorted.
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| 
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|     If x is already in a, insert it to the left of the leftmost x.
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| 
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|     Optional args lo (default 0) and hi (default len(a)) bound the
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|     slice of a to be searched.
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|     """
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| 
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|     if lo < 0:
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|         raise ValueError('lo must be non-negative')
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|     if hi is None:
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|         hi = len(a)
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|     while lo < hi:
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|         mid = (lo+hi)//2
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|         if a[mid] < x: lo = mid+1
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|         else: hi = mid
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|     a.insert(lo, x)
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| 
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| 
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| def bisect_left(a, x, lo=0, hi=None):
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|     """Return the index where to insert item x in list a, assuming a is sorted.
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| 
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|     The return value i is such that all e in a[:i] have e < x, and all e in
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|     a[i:] have e >= x.  So if x already appears in the list, a.insert(x) will
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|     insert just before the leftmost x already there.
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| 
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|     Optional args lo (default 0) and hi (default len(a)) bound the
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|     slice of a to be searched.
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|     """
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| 
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|     if lo < 0:
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|         raise ValueError('lo must be non-negative')
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|     if hi is None:
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|         hi = len(a)
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|     while lo < hi:
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|         mid = (lo+hi)//2
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|         if a[mid] < x: lo = mid+1
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|         else: hi = mid
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|     return lo
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| 
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| # Overwrite above definitions with a fast C implementation
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| try:
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|     from _bisect import *
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| except ImportError:
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|     pass
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