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			19 KiB
		
	
	
	
		
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			638 lines
		
	
	
	
		
			19 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
##  Module statistics.py
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##
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##  Copyright (c) 2013 Steven D'Aprano <steve+python@pearwood.info>.
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##
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##  Licensed under the Apache License, Version 2.0 (the "License");
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##  you may not use this file except in compliance with the License.
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##  You may obtain a copy of the License at
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##
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##  http://www.apache.org/licenses/LICENSE-2.0
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##
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##  Unless required by applicable law or agreed to in writing, software
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##  distributed under the License is distributed on an "AS IS" BASIS,
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##  WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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##  See the License for the specific language governing permissions and
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##  limitations under the License.
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"""
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Basic statistics module.
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This module provides functions for calculating statistics of data, including
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averages, variance, and standard deviation.
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Calculating averages
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--------------------
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==================  =============================================
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Function            Description
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==================  =============================================
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mean                Arithmetic mean (average) of data.
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median              Median (middle value) of data.
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median_low          Low median of data.
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median_high         High median of data.
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median_grouped      Median, or 50th percentile, of grouped data.
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mode                Mode (most common value) of data.
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==================  =============================================
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Calculate the arithmetic mean ("the average") of data:
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>>> mean([-1.0, 2.5, 3.25, 5.75])
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2.625
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Calculate the standard median of discrete data:
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>>> median([2, 3, 4, 5])
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3.5
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Calculate the median, or 50th percentile, of data grouped into class intervals
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centred on the data values provided. E.g. if your data points are rounded to
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the nearest whole number:
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>>> median_grouped([2, 2, 3, 3, 3, 4])  #doctest: +ELLIPSIS
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2.8333333333...
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This should be interpreted in this way: you have two data points in the class
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interval 1.5-2.5, three data points in the class interval 2.5-3.5, and one in
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the class interval 3.5-4.5. The median of these data points is 2.8333...
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Calculating variability or spread
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---------------------------------
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==================  =============================================
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Function            Description
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==================  =============================================
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pvariance           Population variance of data.
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variance            Sample variance of data.
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pstdev              Population standard deviation of data.
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stdev               Sample standard deviation of data.
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==================  =============================================
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Calculate the standard deviation of sample data:
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>>> stdev([2.5, 3.25, 5.5, 11.25, 11.75])  #doctest: +ELLIPSIS
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4.38961843444...
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If you have previously calculated the mean, you can pass it as the optional
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second argument to the four "spread" functions to avoid recalculating it:
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>>> data = [1, 2, 2, 4, 4, 4, 5, 6]
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>>> mu = mean(data)
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>>> pvariance(data, mu)
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2.5
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Exceptions
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----------
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A single exception is defined: StatisticsError is a subclass of ValueError.
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"""
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__all__ = [ 'StatisticsError',
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            'pstdev', 'pvariance', 'stdev', 'variance',
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            'median',  'median_low', 'median_high', 'median_grouped',
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            'mean', 'mode',
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          ]
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import collections
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import math
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from fractions import Fraction
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from decimal import Decimal
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from itertools import groupby
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# === Exceptions ===
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class StatisticsError(ValueError):
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    pass
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# === Private utilities ===
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def _sum(data, start=0):
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    """_sum(data [, start]) -> (type, sum, count)
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    Return a high-precision sum of the given numeric data as a fraction,
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    together with the type to be converted to and the count of items.
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    If optional argument ``start`` is given, it is added to the total.
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    If ``data`` is empty, ``start`` (defaulting to 0) is returned.
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    Examples
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    --------
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    >>> _sum([3, 2.25, 4.5, -0.5, 1.0], 0.75)
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    (<class 'float'>, Fraction(11, 1), 5)
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    Some sources of round-off error will be avoided:
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    >>> _sum([1e50, 1, -1e50] * 1000)  # Built-in sum returns zero.
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    (<class 'float'>, Fraction(1000, 1), 3000)
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    Fractions and Decimals are also supported:
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    >>> from fractions import Fraction as F
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    >>> _sum([F(2, 3), F(7, 5), F(1, 4), F(5, 6)])
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    (<class 'fractions.Fraction'>, Fraction(63, 20), 4)
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    >>> from decimal import Decimal as D
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    >>> data = [D("0.1375"), D("0.2108"), D("0.3061"), D("0.0419")]
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    >>> _sum(data)
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    (<class 'decimal.Decimal'>, Fraction(6963, 10000), 4)
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    Mixed types are currently treated as an error, except that int is
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    allowed.
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    """
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    count = 0
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    n, d = _exact_ratio(start)
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    partials = {d: n}
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    partials_get = partials.get
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    T = _coerce(int, type(start))
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    for typ, values in groupby(data, type):
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        T = _coerce(T, typ)  # or raise TypeError
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        for n,d in map(_exact_ratio, values):
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            count += 1
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            partials[d] = partials_get(d, 0) + n
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    if None in partials:
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        # The sum will be a NAN or INF. We can ignore all the finite
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        # partials, and just look at this special one.
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        total = partials[None]
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        assert not _isfinite(total)
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    else:
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        # Sum all the partial sums using builtin sum.
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        # FIXME is this faster if we sum them in order of the denominator?
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        total = sum(Fraction(n, d) for d, n in sorted(partials.items()))
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    return (T, total, count)
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def _isfinite(x):
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    try:
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        return x.is_finite()  # Likely a Decimal.
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    except AttributeError:
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        return math.isfinite(x)  # Coerces to float first.
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def _coerce(T, S):
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    """Coerce types T and S to a common type, or raise TypeError.
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    Coercion rules are currently an implementation detail. See the CoerceTest
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    test class in test_statistics for details.
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    """
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    # See http://bugs.python.org/issue24068.
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    assert T is not bool, "initial type T is bool"
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    # If the types are the same, no need to coerce anything. Put this
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    # first, so that the usual case (no coercion needed) happens as soon
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    # as possible.
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    if T is S:  return T
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    # Mixed int & other coerce to the other type.
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    if S is int or S is bool:  return T
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    if T is int:  return S
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    # If one is a (strict) subclass of the other, coerce to the subclass.
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    if issubclass(S, T):  return S
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    if issubclass(T, S):  return T
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    # Ints coerce to the other type.
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    if issubclass(T, int):  return S
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    if issubclass(S, int):  return T
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    # Mixed fraction & float coerces to float (or float subclass).
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    if issubclass(T, Fraction) and issubclass(S, float):
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        return S
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    if issubclass(T, float) and issubclass(S, Fraction):
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        return T
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    # Any other combination is disallowed.
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    msg = "don't know how to coerce %s and %s"
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    raise TypeError(msg % (T.__name__, S.__name__))
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def _exact_ratio(x):
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    """Return Real number x to exact (numerator, denominator) pair.
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    >>> _exact_ratio(0.25)
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    (1, 4)
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    x is expected to be an int, Fraction, Decimal or float.
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    """
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    try:
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        # Optimise the common case of floats. We expect that the most often
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        # used numeric type will be builtin floats, so try to make this as
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        # fast as possible.
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        if type(x) is float:
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            return x.as_integer_ratio()
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        try:
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            # x may be an int, Fraction, or Integral ABC.
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            return (x.numerator, x.denominator)
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        except AttributeError:
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            try:
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                # x may be a float subclass.
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                return x.as_integer_ratio()
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            except AttributeError:
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                try:
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                    # x may be a Decimal.
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                    return _decimal_to_ratio(x)
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                except AttributeError:
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                    # Just give up?
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                    pass
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    except (OverflowError, ValueError):
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        # float NAN or INF.
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        assert not math.isfinite(x)
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        return (x, None)
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    msg = "can't convert type '{}' to numerator/denominator"
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    raise TypeError(msg.format(type(x).__name__))
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# FIXME This is faster than Fraction.from_decimal, but still too slow.
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def _decimal_to_ratio(d):
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    """Convert Decimal d to exact integer ratio (numerator, denominator).
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    >>> from decimal import Decimal
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    >>> _decimal_to_ratio(Decimal("2.6"))
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    (26, 10)
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    """
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    sign, digits, exp = d.as_tuple()
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    if exp in ('F', 'n', 'N'):  # INF, NAN, sNAN
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        assert not d.is_finite()
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        return (d, None)
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    num = 0
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    for digit in digits:
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        num = num*10 + digit
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    if exp < 0:
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        den = 10**-exp
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    else:
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        num *= 10**exp
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        den = 1
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    if sign:
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        num = -num
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    return (num, den)
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def _convert(value, T):
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    """Convert value to given numeric type T."""
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    if type(value) is T:
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        # This covers the cases where T is Fraction, or where value is
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        # a NAN or INF (Decimal or float).
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        return value
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    if issubclass(T, int) and value.denominator != 1:
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        T = float
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    try:
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        # FIXME: what do we do if this overflows?
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        return T(value)
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    except TypeError:
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        if issubclass(T, Decimal):
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            return T(value.numerator)/T(value.denominator)
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        else:
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            raise
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def _counts(data):
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    # Generate a table of sorted (value, frequency) pairs.
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    table = collections.Counter(iter(data)).most_common()
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    if not table:
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        return table
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    # Extract the values with the highest frequency.
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    maxfreq = table[0][1]
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    for i in range(1, len(table)):
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        if table[i][1] != maxfreq:
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            table = table[:i]
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            break
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    return table
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# === Measures of central tendency (averages) ===
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def mean(data):
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    """Return the sample arithmetic mean of data.
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    >>> mean([1, 2, 3, 4, 4])
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    2.8
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    >>> from fractions import Fraction as F
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    >>> mean([F(3, 7), F(1, 21), F(5, 3), F(1, 3)])
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    Fraction(13, 21)
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    >>> from decimal import Decimal as D
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    >>> mean([D("0.5"), D("0.75"), D("0.625"), D("0.375")])
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    Decimal('0.5625')
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    If ``data`` is empty, StatisticsError will be raised.
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    """
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    if iter(data) is data:
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        data = list(data)
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    n = len(data)
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    if n < 1:
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        raise StatisticsError('mean requires at least one data point')
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    T, total, count = _sum(data)
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    assert count == n
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    return _convert(total/n, T)
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# FIXME: investigate ways to calculate medians without sorting? Quickselect?
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def median(data):
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    """Return the median (middle value) of numeric data.
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    When the number of data points is odd, return the middle data point.
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    When the number of data points is even, the median is interpolated by
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    taking the average of the two middle values:
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    >>> median([1, 3, 5])
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    3
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    >>> median([1, 3, 5, 7])
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    4.0
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    """
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    data = sorted(data)
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    n = len(data)
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    if n == 0:
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        raise StatisticsError("no median for empty data")
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    if n%2 == 1:
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        return data[n//2]
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    else:
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        i = n//2
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        return (data[i - 1] + data[i])/2
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def median_low(data):
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    """Return the low median of numeric data.
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    When the number of data points is odd, the middle value is returned.
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    When it is even, the smaller of the two middle values is returned.
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    >>> median_low([1, 3, 5])
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    3
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    >>> median_low([1, 3, 5, 7])
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    3
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    """
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    data = sorted(data)
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    n = len(data)
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    if n == 0:
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        raise StatisticsError("no median for empty data")
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    if n%2 == 1:
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        return data[n//2]
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    else:
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        return data[n//2 - 1]
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def median_high(data):
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    """Return the high median of data.
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    When the number of data points is odd, the middle value is returned.
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    When it is even, the larger of the two middle values is returned.
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    >>> median_high([1, 3, 5])
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    3
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    >>> median_high([1, 3, 5, 7])
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    5
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    """
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    data = sorted(data)
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    n = len(data)
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    if n == 0:
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        raise StatisticsError("no median for empty data")
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    return data[n//2]
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def median_grouped(data, interval=1):
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    """Return the 50th percentile (median) of grouped continuous data.
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    >>> median_grouped([1, 2, 2, 3, 4, 4, 4, 4, 4, 5])
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    3.7
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    >>> median_grouped([52, 52, 53, 54])
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    52.5
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    This calculates the median as the 50th percentile, and should be
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    used when your data is continuous and grouped. In the above example,
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    the values 1, 2, 3, etc. actually represent the midpoint of classes
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    0.5-1.5, 1.5-2.5, 2.5-3.5, etc. The middle value falls somewhere in
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    class 3.5-4.5, and interpolation is used to estimate it.
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    Optional argument ``interval`` represents the class interval, and
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    defaults to 1. Changing the class interval naturally will change the
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    interpolated 50th percentile value:
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    >>> median_grouped([1, 3, 3, 5, 7], interval=1)
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    3.25
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    >>> median_grouped([1, 3, 3, 5, 7], interval=2)
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    3.5
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    This function does not check whether the data points are at least
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    ``interval`` apart.
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    """
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    data = sorted(data)
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    n = len(data)
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    if n == 0:
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        raise StatisticsError("no median for empty data")
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    elif n == 1:
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        return data[0]
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    # Find the value at the midpoint. Remember this corresponds to the
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    # centre of the class interval.
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    x = data[n//2]
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    for obj in (x, interval):
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        if isinstance(obj, (str, bytes)):
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            raise TypeError('expected number but got %r' % obj)
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    try:
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        L = x - interval/2  # The lower limit of the median interval.
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    except TypeError:
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        # Mixed type. For now we just coerce to float.
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        L = float(x) - float(interval)/2
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    cf = data.index(x)  # Number of values below the median interval.
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    # FIXME The following line could be more efficient for big lists.
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    f = data.count(x)  # Number of data points in the median interval.
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    return L + interval*(n/2 - cf)/f
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def mode(data):
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    """Return the most common data point from discrete or nominal data.
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    ``mode`` assumes discrete data, and returns a single value. This is the
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    standard treatment of the mode as commonly taught in schools:
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						|
 | 
						|
    >>> mode([1, 1, 2, 3, 3, 3, 3, 4])
 | 
						|
    3
 | 
						|
 | 
						|
    This also works with nominal (non-numeric) data:
 | 
						|
 | 
						|
    >>> mode(["red", "blue", "blue", "red", "green", "red", "red"])
 | 
						|
    'red'
 | 
						|
 | 
						|
    If there is not exactly one most common value, ``mode`` will raise
 | 
						|
    StatisticsError.
 | 
						|
    """
 | 
						|
    # Generate a table of sorted (value, frequency) pairs.
 | 
						|
    table = _counts(data)
 | 
						|
    if len(table) == 1:
 | 
						|
        return table[0][0]
 | 
						|
    elif table:
 | 
						|
        raise StatisticsError(
 | 
						|
                'no unique mode; found %d equally common values' % len(table)
 | 
						|
                )
 | 
						|
    else:
 | 
						|
        raise StatisticsError('no mode for empty data')
 | 
						|
 | 
						|
 | 
						|
# === Measures of spread ===
 | 
						|
 | 
						|
# See http://mathworld.wolfram.com/Variance.html
 | 
						|
#     http://mathworld.wolfram.com/SampleVariance.html
 | 
						|
#     http://en.wikipedia.org/wiki/Algorithms_for_calculating_variance
 | 
						|
#
 | 
						|
# Under no circumstances use the so-called "computational formula for
 | 
						|
# variance", as that is only suitable for hand calculations with a small
 | 
						|
# amount of low-precision data. It has terrible numeric properties.
 | 
						|
#
 | 
						|
# See a comparison of three computational methods here:
 | 
						|
# http://www.johndcook.com/blog/2008/09/26/comparing-three-methods-of-computing-standard-deviation/
 | 
						|
 | 
						|
def _ss(data, c=None):
 | 
						|
    """Return sum of square deviations of sequence data.
 | 
						|
 | 
						|
    If ``c`` is None, the mean is calculated in one pass, and the deviations
 | 
						|
    from the mean are calculated in a second pass. Otherwise, deviations are
 | 
						|
    calculated from ``c`` as given. Use the second case with care, as it can
 | 
						|
    lead to garbage results.
 | 
						|
    """
 | 
						|
    if c is None:
 | 
						|
        c = mean(data)
 | 
						|
    T, total, count = _sum((x-c)**2 for x in data)
 | 
						|
    # The following sum should mathematically equal zero, but due to rounding
 | 
						|
    # error may not.
 | 
						|
    U, total2, count2 = _sum((x-c) for x in data)
 | 
						|
    assert T == U and count == count2
 | 
						|
    total -=  total2**2/len(data)
 | 
						|
    assert not total < 0, 'negative sum of square deviations: %f' % total
 | 
						|
    return (T, total)
 | 
						|
 | 
						|
 | 
						|
def variance(data, xbar=None):
 | 
						|
    """Return the sample variance of data.
 | 
						|
 | 
						|
    data should be an iterable of Real-valued numbers, with at least two
 | 
						|
    values. The optional argument xbar, if given, should be the mean of
 | 
						|
    the data. If it is missing or None, the mean is automatically calculated.
 | 
						|
 | 
						|
    Use this function when your data is a sample from a population. To
 | 
						|
    calculate the variance from the entire population, see ``pvariance``.
 | 
						|
 | 
						|
    Examples:
 | 
						|
 | 
						|
    >>> data = [2.75, 1.75, 1.25, 0.25, 0.5, 1.25, 3.5]
 | 
						|
    >>> variance(data)
 | 
						|
    1.3720238095238095
 | 
						|
 | 
						|
    If you have already calculated the mean of your data, you can pass it as
 | 
						|
    the optional second argument ``xbar`` to avoid recalculating it:
 | 
						|
 | 
						|
    >>> m = mean(data)
 | 
						|
    >>> variance(data, m)
 | 
						|
    1.3720238095238095
 | 
						|
 | 
						|
    This function does not check that ``xbar`` is actually the mean of
 | 
						|
    ``data``. Giving arbitrary values for ``xbar`` may lead to invalid or
 | 
						|
    impossible results.
 | 
						|
 | 
						|
    Decimals and Fractions are supported:
 | 
						|
 | 
						|
    >>> from decimal import Decimal as D
 | 
						|
    >>> variance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")])
 | 
						|
    Decimal('31.01875')
 | 
						|
 | 
						|
    >>> from fractions import Fraction as F
 | 
						|
    >>> variance([F(1, 6), F(1, 2), F(5, 3)])
 | 
						|
    Fraction(67, 108)
 | 
						|
 | 
						|
    """
 | 
						|
    if iter(data) is data:
 | 
						|
        data = list(data)
 | 
						|
    n = len(data)
 | 
						|
    if n < 2:
 | 
						|
        raise StatisticsError('variance requires at least two data points')
 | 
						|
    T, ss = _ss(data, xbar)
 | 
						|
    return _convert(ss/(n-1), T)
 | 
						|
 | 
						|
 | 
						|
def pvariance(data, mu=None):
 | 
						|
    """Return the population variance of ``data``.
 | 
						|
 | 
						|
    data should be an iterable of Real-valued numbers, with at least one
 | 
						|
    value. The optional argument mu, if given, should be the mean of
 | 
						|
    the data. If it is missing or None, the mean is automatically calculated.
 | 
						|
 | 
						|
    Use this function to calculate the variance from the entire population.
 | 
						|
    To estimate the variance from a sample, the ``variance`` function is
 | 
						|
    usually a better choice.
 | 
						|
 | 
						|
    Examples:
 | 
						|
 | 
						|
    >>> data = [0.0, 0.25, 0.25, 1.25, 1.5, 1.75, 2.75, 3.25]
 | 
						|
    >>> pvariance(data)
 | 
						|
    1.25
 | 
						|
 | 
						|
    If you have already calculated the mean of the data, you can pass it as
 | 
						|
    the optional second argument to avoid recalculating it:
 | 
						|
 | 
						|
    >>> mu = mean(data)
 | 
						|
    >>> pvariance(data, mu)
 | 
						|
    1.25
 | 
						|
 | 
						|
    This function does not check that ``mu`` is actually the mean of ``data``.
 | 
						|
    Giving arbitrary values for ``mu`` may lead to invalid or impossible
 | 
						|
    results.
 | 
						|
 | 
						|
    Decimals and Fractions are supported:
 | 
						|
 | 
						|
    >>> from decimal import Decimal as D
 | 
						|
    >>> pvariance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")])
 | 
						|
    Decimal('24.815')
 | 
						|
 | 
						|
    >>> from fractions import Fraction as F
 | 
						|
    >>> pvariance([F(1, 4), F(5, 4), F(1, 2)])
 | 
						|
    Fraction(13, 72)
 | 
						|
 | 
						|
    """
 | 
						|
    if iter(data) is data:
 | 
						|
        data = list(data)
 | 
						|
    n = len(data)
 | 
						|
    if n < 1:
 | 
						|
        raise StatisticsError('pvariance requires at least one data point')
 | 
						|
    ss = _ss(data, mu)
 | 
						|
    T, ss = _ss(data, mu)
 | 
						|
    return _convert(ss/n, T)
 | 
						|
 | 
						|
 | 
						|
def stdev(data, xbar=None):
 | 
						|
    """Return the square root of the sample variance.
 | 
						|
 | 
						|
    See ``variance`` for arguments and other details.
 | 
						|
 | 
						|
    >>> stdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75])
 | 
						|
    1.0810874155219827
 | 
						|
 | 
						|
    """
 | 
						|
    var = variance(data, xbar)
 | 
						|
    try:
 | 
						|
        return var.sqrt()
 | 
						|
    except AttributeError:
 | 
						|
        return math.sqrt(var)
 | 
						|
 | 
						|
 | 
						|
def pstdev(data, mu=None):
 | 
						|
    """Return the square root of the population variance.
 | 
						|
 | 
						|
    See ``pvariance`` for arguments and other details.
 | 
						|
 | 
						|
    >>> pstdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75])
 | 
						|
    0.986893273527251
 | 
						|
 | 
						|
    """
 | 
						|
    var = pvariance(data, mu)
 | 
						|
    try:
 | 
						|
        return var.sqrt()
 | 
						|
    except AttributeError:
 | 
						|
        return math.sqrt(var)
 |