Remove databricks dialect guard

This commit is contained in:
James Vorderbruggen 2025-12-18 07:15:33 -06:00
parent d0bed07152
commit b3534992a0

View file

@ -15358,9 +15358,7 @@ impl<'a> Parser<'a> {
let func_name = self.parse_object_name(true)?;
let func = self.parse_function(func_name)?;
return Ok(Some(TableVersion::Function(func)));
} else if dialect_of!(self is DatabricksDialect)
&& self.parse_keywords(&[Keyword::TIMESTAMP, Keyword::AS, Keyword::OF])
{
} else if self.parse_keywords(&[Keyword::TIMESTAMP, Keyword::AS, Keyword::OF]) {
let expr = self.parse_expr()?;
return Ok(Some(TableVersion::TimestampAsOf(expr)));
}