// Case 1: Even though we shadow `x` later, the capture is for the earlier
// definition.
let x = 42;
let f = y => x + y;
let x = 0;
// Should return 43, not 1.
let r1 = f(1);

// Case 2: The function arguments shadow any previously defined variables.
let x = 42;
let f = x => x + 1;
// Should return 1, not 43.
let r2 = f(0);

// Case 3: The captures can be different even for a function at the same source
// location.
let fs = [for k in [1, 2, 3]: x => x + k];
let r3 = [for f in fs: f(10)];

{ r1 = r1, r2 = r2, r3 = r3 }

# output:
{"r1": 43, "r2": 1, "r3": [11, 12, 13]}