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[red-knot] type[T]
is disjoint from type[S]
if the metaclass of T
is disjoint from the metaclass of S
(#15547)
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4 changed files with 59 additions and 21 deletions
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@ -246,3 +246,31 @@ def _(x: type, y: type[int]):
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if issubclass(x, y):
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reveal_type(x) # revealed: type[int]
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```
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### Disjoint `type[]` types are narrowed to `Never`
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Here, `type[UsesMeta1]` and `type[UsesMeta2]` are disjoint because a common subclass of `UsesMeta1`
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and `UsesMeta2` could only exist if a common subclass of their metaclasses could exist. This is
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known to be impossible due to the fact that `Meta1` is marked as `@final`.
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```py
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from typing import final
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@final
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class Meta1(type): ...
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class Meta2(type): ...
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class UsesMeta1(metaclass=Meta1): ...
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class UsesMeta2(metaclass=Meta2): ...
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def _(x: type[UsesMeta1], y: type[UsesMeta2]):
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if issubclass(x, y):
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reveal_type(x) # revealed: Never
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else:
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reveal_type(x) # revealed: type[UsesMeta1]
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if issubclass(y, x):
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reveal_type(y) # revealed: Never
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else:
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reveal_type(y) # revealed: type[UsesMeta2]
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```
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@ -37,3 +37,22 @@ class UsesMeta2(metaclass=Meta2): ...
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static_assert(not is_disjoint_from(Meta2, type[UsesMeta2]))
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static_assert(is_disjoint_from(Meta1, type[UsesMeta2]))
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```
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## `type[T]` versus `type[S]`
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By the same token, `type[T]` is disjoint from `type[S]` if the metaclass of `T` is disjoint from the
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metaclass of `S`.
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```py
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from typing import final
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from knot_extensions import static_assert, is_disjoint_from
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@final
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class Meta1(type): ...
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class Meta2(type): ...
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class UsesMeta1(metaclass=Meta1): ...
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class UsesMeta2(metaclass=Meta2): ...
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static_assert(is_disjoint_from(type[UsesMeta1], type[UsesMeta2]))
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```
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@ -1276,21 +1276,6 @@ impl<'db> Type<'db> {
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ClassBase::Class(class_a) => !class_b.is_subclass_of(db, class_a),
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},
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(Type::SubclassOf(_), Type::SubclassOf(_)) => false,
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(Type::SubclassOf(subclass_of_ty), instance @ Type::Instance(_))
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| (instance @ Type::Instance(_), Type::SubclassOf(subclass_of_ty)) => {
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// `type[T]` is disjoint from `S`, where `S` is an instance type,
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// if `U` is disjoint from `S`,
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// where `U` represents all instances of `T`'s metaclass
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let metaclass_instance = subclass_of_ty
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.subclass_of()
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.into_class()
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.map(|class| class.metaclass(db).to_instance(db))
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.unwrap_or_else(|| KnownClass::Type.to_instance(db));
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instance.is_disjoint_from(db, metaclass_instance)
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}
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(
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Type::SubclassOf(_),
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Type::BooleanLiteral(..)
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@ -1324,12 +1309,9 @@ impl<'db> Type<'db> {
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ty.bool(db).is_always_true()
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}
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(Type::SubclassOf(_), other) | (other, Type::SubclassOf(_)) => {
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// TODO we could do better here: if both variants are `SubclassOf` and they have different "solid bases",
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// multiple inheritance between the two is impossible, so they are disjoint.
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//
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// Note that `type[<@final class>]` is eagerly simplified to `Literal[<@final class>]` by [`SubclassOfType::from`].
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other.is_disjoint_from(db, KnownClass::Type.to_instance(db))
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(Type::SubclassOf(subclass_of_ty), other)
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| (other, Type::SubclassOf(subclass_of_ty)) => {
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other.is_disjoint_from(db, subclass_of_ty.as_instance_type_of_metaclass(db))
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}
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(Type::KnownInstance(known_instance), Type::Instance(InstanceType { class }))
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@ -68,6 +68,15 @@ impl<'db> SubclassOfType<'db> {
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Type::from(self.subclass_of).member(db, name)
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}
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/// A class `T` is an instance of its metaclass `U`,
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/// so the type `type[T]` is a subtype of the instance type `U`.
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pub(crate) fn as_instance_type_of_metaclass(&self, db: &'db dyn Db) -> Type<'db> {
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match self.subclass_of {
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ClassBase::Dynamic(_) => KnownClass::Type.to_instance(db),
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ClassBase::Class(class) => class.metaclass(db).to_instance(db),
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}
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}
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/// Return `true` if `self` is a subtype of `other`.
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///
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/// This can only return `true` if `self.subclass_of` is a [`ClassBase::Class`] variant;
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