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[red-knot] Avoid unresolved-reference in unreachable code (#17169)
## Summary This PR changes the inferred type for symbols in unreachable sections of code to `Never` (instead of reporting them as unbound), in order to silence false positive diagnostics. See the lengthy comment in the code for further details. ## Test Plan - Updated Markdown tests. - Manually verified a couple of ecosystem diagnostic changes.
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3 changed files with 48 additions and 8 deletions
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@ -654,9 +654,7 @@ def f(cond: bool) -> str:
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reveal_type(x) # revealed: Literal["before"]
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return "a"
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x = "after-return"
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# TODO: no unresolved-reference error
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# error: [unresolved-reference]
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reveal_type(x) # revealed: Unknown
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reveal_type(x) # revealed: Never
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else:
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x = "else"
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return reveal_type(x) # revealed: Literal["else"]
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@ -211,9 +211,6 @@ def f():
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print("unreachable")
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# TODO: we should not emit an error here; we currently do, since there is no control flow path from this
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# use of 'x' to any definition of 'x'.
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# error: [unresolved-reference]
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print(x)
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```
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@ -228,8 +225,6 @@ def outer():
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x = 1
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def inner():
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# TODO: we should not emit an error here
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# error: [unresolved-reference]
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return x # Name `x` used when not defined
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while True:
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pass
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@ -679,6 +679,53 @@ fn symbol_from_bindings_impl<'db>(
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visibility_constraints.evaluate(db, predicates, visibility_constraint);
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if static_visibility.is_always_false() {
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// We found a binding that we have statically determined to not be visible from
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// the use of the symbol that we are investigating. There are three interesting
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// cases to consider:
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//
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// ```py
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// def f1():
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// if False:
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// x = 1
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// use(x)
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//
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// def f2():
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// y = 1
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// return
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// use(y)
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//
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// def f3(flag: bool):
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// z = 1
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// if flag:
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// z = 2
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// return
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// use(z)
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// ```
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//
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// In the first case, there is a single binding for `x`, and due to the statically
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// known `False` condition, it is not visible at the use of `x`. However, we *can*
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// see/reach the start of the scope from `use(x)`. This means that `x` is unbound
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// and we should return `None`.
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//
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// In the second case, `y` is also not visible at the use of `y`, but here, we can
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// not see/reach the start of the scope. There is only one path of control flow,
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// and it passes through that binding of `y` (which we can not see). This implies
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// that we are in an unreachable section of code. We return `Never` in order to
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// silence the `unresolve-reference` diagnostic that would otherwise be emitted at
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// the use of `y`.
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//
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// In the third case, we have two bindings for `z`. The first one is visible, so we
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// consider the case that we now encounter the second binding `z = 2`, which is not
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// visible due to the early return. We *also* can not see the start of the scope
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// from `use(z)` because both paths of control flow pass through a binding of `z`.
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// The `z = 1` binding is visible, and so we are *not* in an unreachable section of
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// code. However, it is still okay to return `Never` in this case, because we will
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// union the types of all bindings, and `Never` will be eliminated automatically.
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if unbound_visibility.is_always_false() {
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// The scope-start is not visible
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return Some(Type::Never);
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}
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return None;
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}
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