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[ty] Consistent use of American english (in rules) (#19488 )

## Summary

Just noticed this as a minor inconsistency in our rules, and had Claude
do a few more automated replacements.

2025-07-22 16:10:38 +02:00

1.7 KiB

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Union

Annotation

typing.Union can be used to construct union types in the same way as the | operator.

from typing import Union

a: Union[int, str]
a1: Union[int, bool]
a2: Union[int, Union[bytes, str]]
a3: Union[int, None]
a4: Union[Union[bytes, str]]
a5: Union[int]
a6: Union[()]

def f():
    # revealed: int | str
    reveal_type(a)
    # Since bool is a subtype of int we simplify to int here. But we do allow assigning boolean values (see below).
    # revealed: int
    reveal_type(a1)
    # revealed: int | bytes | str
    reveal_type(a2)
    # revealed: int | None
    reveal_type(a3)
    # revealed: bytes | str
    reveal_type(a4)
    # revealed: int
    reveal_type(a5)
    # revealed: Never
    reveal_type(a6)

Assignment

from typing import Union

a: Union[int, str]
a = 1
a = ""
a1: Union[int, bool]
a1 = 1
a1 = True
# error: [invalid-assignment] "Object of type `Literal[b""]` is not assignable to `int | str`"
a = b""

Typing Extensions

from typing_extensions import Union

a: Union[int, str]

def f():
    # revealed: int | str
    reveal_type(a)

Invalid

from typing import Union

# error: [invalid-type-form] "`typing.Union` requires at least one argument when used in a type expression"
def f(x: Union) -> None:
    reveal_type(x)  # revealed: Unknown

Implicit type aliases using new-style unions

We don't recognize these as type aliases yet, but we also don't emit false-positive diagnostics if you use them in type expressions:

[environment]
python-version = "3.10"

X = int | str

def f(y: X):
    reveal_type(y)  # revealed: @Todo(Support for `types.UnionType` instances in type expressions)

1.7 KiB Raw Blame History