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1.9 KiB
1.9 KiB
Binary operations on tuples
Concatenation for heterogeneous tuples
reveal_type((1, 2) + (3, 4)) # revealed: tuple[Literal[1, 2, 3, 4], ...]
reveal_type(() + (1, 2)) # revealed: tuple[Literal[1, 2], ...]
reveal_type((1, 2) + ()) # revealed: tuple[Literal[1, 2], ...]
reveal_type(() + ()) # revealed: tuple[()]
def _(x: tuple[int, str], y: tuple[None, tuple[int]]):
reveal_type(x + y) # revealed: tuple[int | str | None | tuple[int], ...]
reveal_type(y + x) # revealed: tuple[None | tuple[int] | int | str, ...]
Concatenation for homogeneous tuples
def _(x: tuple[int, ...], y: tuple[str, ...]):
reveal_type(x + x) # revealed: tuple[int, ...]
reveal_type(x + y) # revealed: tuple[int | str, ...]
reveal_type((1, 2) + x) # revealed: tuple[int, ...]
reveal_type(x + (3, 4)) # revealed: tuple[int, ...]
reveal_type((1, 2) + x + (3, 4)) # revealed: tuple[int, ...]
reveal_type((1, 2) + y + (3, 4) + x) # revealed: tuple[int | str, ...]
We get the same results even when we use a legacy type alias, even though this involves first
inferring the tuple[...]
expression as a value form. (Doing so gives a generic alias of the
tuple
type, but as a special case, we include the full detailed tuple element specification in
specializations of tuple
.)
from typing import Literal
OneTwo = tuple[Literal[1], Literal[2]]
ThreeFour = tuple[Literal[3], Literal[4]]
IntTuple = tuple[int, ...]
StrTuple = tuple[str, ...]
def _(one_two: OneTwo, x: IntTuple, y: StrTuple, three_four: ThreeFour):
reveal_type(x + x) # revealed: tuple[int, ...]
reveal_type(x + y) # revealed: tuple[int | str, ...]
reveal_type(one_two + x) # revealed: tuple[int, ...]
reveal_type(x + three_four) # revealed: tuple[int, ...]
reveal_type(one_two + x + three_four) # revealed: tuple[int, ...]
reveal_type(one_two + y + three_four + x) # revealed: tuple[int | str, ...]