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2.5 KiB
2.5 KiB
Comparison: Unions
Union on one side of the comparison
Comparisons on union types need to consider all possible cases:
def _(flag: bool):
one_or_two = 1 if flag else 2
reveal_type(one_or_two <= 2) # revealed: Literal[True]
reveal_type(one_or_two <= 1) # revealed: bool
reveal_type(one_or_two <= 0) # revealed: Literal[False]
reveal_type(2 >= one_or_two) # revealed: Literal[True]
reveal_type(1 >= one_or_two) # revealed: bool
reveal_type(0 >= one_or_two) # revealed: Literal[False]
reveal_type(one_or_two < 1) # revealed: Literal[False]
reveal_type(one_or_two < 2) # revealed: bool
reveal_type(one_or_two < 3) # revealed: Literal[True]
reveal_type(one_or_two > 0) # revealed: Literal[True]
reveal_type(one_or_two > 1) # revealed: bool
reveal_type(one_or_two > 2) # revealed: Literal[False]
reveal_type(one_or_two == 3) # revealed: Literal[False]
reveal_type(one_or_two == 1) # revealed: bool
reveal_type(one_or_two != 3) # revealed: Literal[True]
reveal_type(one_or_two != 1) # revealed: bool
a_or_ab = "a" if flag else "ab"
reveal_type(a_or_ab in "ab") # revealed: Literal[True]
reveal_type("a" in a_or_ab) # revealed: Literal[True]
reveal_type("c" not in a_or_ab) # revealed: Literal[True]
reveal_type("a" not in a_or_ab) # revealed: Literal[False]
reveal_type("b" in a_or_ab) # revealed: bool
reveal_type("b" not in a_or_ab) # revealed: bool
one_or_none = 1 if flag else None
reveal_type(one_or_none is None) # revealed: bool
reveal_type(one_or_none is not None) # revealed: bool
Union on both sides of the comparison
With unions on both sides, we need to consider the full cross product of options when building the resulting (union) type:
def _(flag_s: bool, flag_l: bool):
small = 1 if flag_s else 2
large = 2 if flag_l else 3
reveal_type(small <= large) # revealed: Literal[True]
reveal_type(small >= large) # revealed: bool
reveal_type(small < large) # revealed: bool
reveal_type(small > large) # revealed: Literal[False]
Unsupported operations
Make sure we emit a diagnostic if any of the possible comparisons is unsupported. For now, we fall
back to bool
for the result type instead of trying to infer something more precise from the other
(supported) variants:
def _(flag: bool):
x = [1, 2] if flag else 1
result = 1 in x # error: "Operator `in` is not supported"
reveal_type(result) # revealed: bool